Answer:
the answer should be a constant
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Answer:
(a)
= 0.22 W
(b)
= 0.056 W
Explanation:
given information:
the mass of piano wire, m = 3.00 g = 0.003 kg
tension, F = 25 N
length, l = 80 cm = 0.8 m
frequency, f = 120 Hz
amplitude, A = 1.6 mm = 0.0016 m
(a) the average power carried by the wave, 
=
(√μF)ω²A²
where,
ω = 2πf = 2π120 = 754
μ = 
= 
= 0.00375 kg/m
thus,
=
(√(0.00375)(25))(754)²(0.0016)²
= 0.22 W
(b) What happens to the average power if the wave amplitude is halved.
based on the equation above, we know that the average power is proportional to the square amplitude. therefore


= 
= 0.056 W
Answer:
The acceleration of the box is 2.
Explanation:
According to Newton's second law of motion, the acceleration of any object will be directly proportional to the net unbalanced force acting on the object and inversely proportional to the mass of the object.
Net force = Mass × Acceleration
So 
Since in this case, the box is experiencing a force from east of magnitude 27 N and resisting force of about 17 N from west. So the net force will be the difference of acting and reacting force.
Net force = 27-17 = 10 N.
Thus, 
So 2
is the acceleration of the box. Thus the magnitude of acceleration of the box is 2.
Answer:
d. may be either greater, smaller, or equal to that observed inside the bus.
Explanation:
- The bus is moving at a constant speed. The ball tossed and received by the ball is inside the bus at a speed equal to the speed of the ball. Therefore the speed of the bus becomes zero with respect to the observer inside the bus.
- Now the observer inside the bus noticed the ball from the inside of the bus, so he threw the ball back and forth from the ball with the speed v relative to the observer.
- Now the observer outside the bus could see the bus moving at speed relative to its reference point and also throwing the ball from front to back. The speed of the ball to the observer outside the bus The speed of the bus to the observer outside the bus is minus the speed of the ball to the observer inside the bus.
- Therefore, the ball speed = (u-v) relative to the observer outside the bus.
Could there be any options to this one?