Volume by Displacement. The displacement method (submersion, or dunking method) can be used to accurately measure the volume of the human body and other oddly shaped objects by measuring the volume of fluid displaced when the object is submerged.
The following precautions should be taken very observantly:-
The line of sight must be perpendicular to measuring scale to avoid parallax error. Formation of bubbles inside the cylinder should be completely avoided. Any bubbles within leads to wrong measurements.
Answer:
When there is wind it takes longer
Explanation:
With no wind, the round trip time is

When we have a constant wind speed w

comparing the reciprocal times;

This means that t1 is smaller than t2, ergo, it takes longer with wind
Answer:
a)
, with a magnitude of 
b)
, with a magnitude of 
c)
, with a magnitude of 
Explanation:
We have:

We can calculate each component of the acceleration using its definition 

The rate of change of momentum of the ball is 
So for each coordinate:

And these are equal to the components of the net force since F=ma.
If magnitudes is what is asked:

<em>(N and </em>
<em> are the same unit).</em>
The correct answer is D. the star is getting farther away.
When the light has red-shifted, it shows that everything is moving away from a certain point. This is known as the Doppler effect and proves the Big Bang (which would be the center point that everything is moving away from). Just as a 'for your information', blue shift is when the star is moving towards us.
Hope I helped :)
Resitance (R)= 10 Ohm
Potential difference (V) = 9V
V= IR
I= V/R
I= 9/10
I= 0.9 Ampere
Therefore 0.9 Ampere of current is flowing through the circuit.