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ddd [48]
3 years ago
5

Suppose the frameshift mutation was still present, but now there was a base substitution (A to C) in the arginine (R) codon, cha

nging it from AGA to AGC. Original Sequence: 5' - UG | GUC | GGC | GAG | AAC | GAA | AGC | GC - 3' Mutated Sequence: 5' - UG | GUC | GGG | AGC | ACG | AAA | GCG | C - 3' Would the function of the protein be restored? Choose the best answer. A. No, while the serine is present in the protein, the rest of the mRNA is still out of frame. B. Yes, the reading frame has been restored and now the serine can be phosphorylated. C. Yes, now the serine can be phosphorylated. D. No, while the serine is is present, it is not in the same location as the original protein. Even though the rest of the protein is functional, shifting the amino acid a few positions would likely not allow it to be phosphorylated.
Biology
1 answer:
maksim [4K]3 years ago
7 0

Answer:

A. The rest is still out of frame

Explanation:

The mRNA codon translated to amino acids is placed below.

While serine, which is one of the amino acids in the original protein, is still there as a part of the new sequence, there are a host of other frame shift mutations. While it is possible to phosphorylate a serine in any of these amino acid sequences, the secondary and tertiary structure of these are different to each other.

Original:

5' - UG | GUC | GGC | GAG | AAC | GAA | AGC | GC - 3'  

              Val     Gly      Glu      Asn     Glu      Ser

Mutation:

5' - UG | GUC | GGG | AGC | ACG | AAA | GCG | C - 3'

              Val      Gly      Ser      Thr     Lys      Ala      

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Explanation:

We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.

DF=\frac{Vi}{Vf}

<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>

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