2thousands pluse 14hundreds
2 answers:
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Given:
baked: 6 <span>cookies and 4 brownies
can bake 25 more either </span><span>cookies or brownies
</span><span>Let x represent the number of more cookies that Midge can bake
Let y represent the number of more brownies that Midge can bake.
cookies = 6 + x
brownies = 4 + y
(6 + x) + (4 +y) </span>≤ 25
10 + x + y ≤ 25
x + y ≤ 25 - 10
x + y ≤<span> 15
y </span>≤ <span>15 - x
</span><span>The following graphs best represents the relationship between x and y is:
</span>
<span>line joining ordered pair 0, 15 and 7, 8 and the region below this line which lies in the first quadrant is shaded</span><span>
</span>
baked: 6 <span>cookies and 4 brownies
can bake 25 more either </span><span>cookies or brownies
</span><span>Let x represent the number of more cookies that Midge can bake
Let y represent the number of more brownies that Midge can bake.
cookies = 6 + x
brownies = 4 + y
(6 + x) + (4 +y) </span>≤ 25
10 + x + y ≤ 25
x + y ≤ 25 - 10
x + y ≤<span> 15
y </span>≤ <span>15 - x
</span><span>The following graphs best represents the relationship between x and y is:
</span>
<span>line joining ordered pair 0, 15 and 7, 8 and the region below this line which lies in the first quadrant is shaded</span><span>
</span>
let's firstly conver the mixed fractions to improper fractions and then get their product.
hmmm I take it that one can write that mixed as .
is valid, not that it makes any sense.