R^2+(ab)^2= (ao)^2
ab=6
ao=11.7
Plug in
r^2+6^2=11.7^2
simplify
r^2+36= 136.89
-36 both sides
r^2=100.89
square root both sides
r= 10.04 rounded 10
To solve this problem, we use the formula:
z = (x – u) / s
where z is the z score value which can be obtained from
the tables, x is the sample value, u is the mean = 6.3 min, and s is the std
dev = 2.2 min
at P value = 0.90, the z = 1.28, finding for x:
x = z s + u
x = 1.28 * 2.2 + 6.3
x = 9.116
at P value = 1.0, the z = 3.49, finding for x:
x = z s + u
x = 3.49 * 2.2 + 6.3
x = 13.978 ~ 14
Therefore the longest 10% calls last about 9.1 minutes to
14 minutes
From the graph: there are 200 students overall. For the next 100, we can divide each number by 2 to find an estimate for how many with participate in MATH tutoring. 40 divided by 2 =20 students participating in MATH tutoring.
Part B- There are currently 55 students out of 200 in SCIENCE tutoring. We add 55 more for 400 = 110, add 55 more for 600=165, and then add half of 55 (27.5 or 28 because you CANNOT have half a student) for 700 students total. 55+55+55+28=193 students.
36 / 9 equals 4 so the problem is basically 10 + 4 which is 14.
