The disk method will only involve a single integral. I've attached a sketch of the bounded region (in red) and one such disk made by revolving it around the y-axis.
Such a disk has radius x = 1/y and height/thickness ∆y, so that the volume of one such disk is
π (radius) (height) = π (1/y)² ∆y = π/y² ∆y
and the volume of a stack of n such disks is

where
is a point sampled from the interval [1, 5].
As we refine the solid by adding increasingly more, increasingly thinner disks, so that ∆y converges to 0, the sum converges to a definite integral that gives the exact volume V,


Answer:
1/2,3/6,5/10,8/16
Step-by-step explanation:
they all equal 1/2
Im not sure if thats what it was asking but yea
Answer:
8 3/8
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
12/3=4
57/3=19
<u>Answer:
</u>
The standard form of
is 20,00,0000
<u>Solution:
</u>
Given that
---- eqn 1
To write
in standard form,
We know that
.So
becomes
.
Now eqn 1 becomes,
----- eqn 2
We know that
, so 
Now eqn 2 becomes,

---- eqn 3
Expanding
:
Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

Now eqn 3 becomes,

= 20,00,0000
Hence the standard form of
is 20,00,0000