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shepuryov [24]
3 years ago
13

Suppose the number of corn kernels on an ear of corn is normally distributed. For a random sample of ears of corn, the confidenc

e interval (858.50, 885.50) is generated. Find the error bound.
Mathematics
1 answer:
Dafna11 [192]3 years ago
6 0

Answer:

The error bound is of 13.5 corn kernels.

Step-by-step explanation:

Any confidence interval has a lower bound and an upper bound. The error bound is the difference between the values of those two bounds, divided by 2.

In this problem, we have that:

Lower bound: 858.50

Upper bound: 885.50

Error bound: (885.50-858.50)/2 = 13.5

The error bound is of 13.5 corn kernels.

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The circumference of a sphere was measured to be 82 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma
NeTakaya

Answer:

The Maximum error is  26cm^2

Step-by-step explanation:

Given that the circumference of a sphere was measured to be 82 cm with a possible error of 0.5 cm

<h3>To find :</h3><h3>(a) Use differentials to estimate the maximum error in the calculated surface area. (Round your answer to the nearest integer.) cm^2</h3>

Given circumference of a sphere=82 cm and possible error =0.5 cm

Error of the surface area is dA

Error of circumference is dC = 0.5 cm

We know that the formula for  Circumference of a sphere is C=2πr units  

Differentiating with respect to r

 dC = 2\pi dr

dr =\frac{dC}{2π}

=\frac{0.5}{2\pi} (∵ dC = 0.5 cm)

<h3>Since Area  A = 4\pi r^2 square units</h3>

Differentiating with respect to r

dA = 8\pi rdr  square units

Since given C = 82 cm.and also C=2πr  we have

r=\frac{C}{2π}

=\frac{82}{2π}

r=\frac{41}{π}

From that dA = 8\pi rdr

Substituting the values of r and dr in the above equation we get

dA = 8\pi (\frac{41}{\pi}) (\frac{0.5}{2\pi})

=4(41)\times (\frac{0.5}{3.14})

=26.1146

dA=26cm^2

∴  Maximum error is  26cm^2

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possible derivation:

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Answer:

x = 7

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3 years ago
Read 2 more answers
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