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2 years ago

Let m and n be two positive integers greater than 1 . If

Mathematics

1 answer:

sammy [17]2 years ago

3 0

<h2>SOLUTION :-</h2>

PLEASE CHECK THE ATTACHED FILE

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Write the word sentence as an inequality<br> A number y divided by 6 is no more than 2

Sedbober [7]

Answer:

Y/6 <_ 2

Step-by-step explanation:

(Less than it equal to sign)

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2 years ago

Which statement is true?<br> A. .8>.79<br> B. .4>.40<br> C. .76>1.2<br> D. .80>.9

Hitman42 [59]

It is A. Because .8 is the same has saying .80, it is .80>.79, and 80 is greater than 79

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3 years ago

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Please help with this question

zvonat [6]

6-10+2 solve from left to right and your answer should be -2

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3 years ago

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=

Leno4ka [110]

1 step: $S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}$ , $S_{3}=T_{1}+T_{2}+T_{3}$ , then
$S_{5}-S_{3}=T_{4}+T_{5}=5$ .

2 step: $T_{n}=T_{1}*q^{n-1}$ , then
$T_{6}=T_{1}*q^{5}$
$T_{5}=T_{1}*q^{4}$
$T_{4}=T_{1}*q^{3}$
$T_{3}=T_{1}*q^{2}$
and $\left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right.$ will have form $\left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right.$ and dividing first equation on second we obtain $\frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}$ . So, $\frac{(q-1)(q+1)}{q+1} = \frac{1}{2}$ and $q-1= \frac{1}{2}$ , $q= \frac{3}{2}$ - the common ratio.

4 step: Insert $q= \frac{3}{2}$ into equation $T_{1}*q^{3}*(q+1)=5$ and obtain $T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5$ , from where $T_{1}= \frac{16}{27}$ .

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3 years ago

How many feet are in 12 yards ,2 feet

Luba_88 [7]

Answer:

Step-by-step explanation:

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3 years ago

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