2 years ago

Let m and n be two positive integers greater than 1 . If

Mathematics

1 answer:

sammy [17]2 years ago

3 0

<h2>SOLUTION :-</h2>

PLEASE CHECK THE ATTACHED FILE

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14 and 7/8 cups of flour

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3 years ago

The sum of two consecutive integers is at least negative fifteen. What are the smallest values of consecutive integers that will

Paladinen [302]

Hello,

Your answer would be:

Let x = the first integer
x + 1 = the next consecutive integer

x + (x + 1) ≥ -15
2x + 1 ≥ -15
- 1 - 1
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2 2
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Plz mark me brainliest!

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4 years ago

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Solve the quadratic equation using the quadratic formula: 3x^2 - 6x = 5

Fantom [35]

Answer:

$x_{1} = 1+\frac{2\sqrt{6}}{3} \\\\x_{2} = 1-\frac{2\sqrt{6}}{3}$

Step-by-step explanation:

3x^2 - 6x - 5=0

quadratic formula:

$x=\frac{-b+-\sqrt{b^{2}-4*a*c}}{2*a}$

a=3 b=-6 c=-5

$x=\frac{-(-6)+-\sqrt{(-6)^{2}-4*3*-5}}{2*3}$

$x=\frac{6+-\sqrt{36+60}}{6} \\\\x=\frac{6+-\sqrt{96}}{6} \\\\x=\frac{6+-\sqrt{2^{2}*2^{2}*2*3 }}{6} \\\\x=\frac{6+-4\sqrt{6}}{6} \\$

so we have:

$x_{1} = 1+\frac{2\sqrt{6}}{3} \\\\x_{2} = 1-\frac{2\sqrt{6}}{3}$

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If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

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Step-by-step explanation:

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rewona [7]

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Step-by-step explanation:

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