Answer:
x^2 + y^2 + 16x + 6y + 9 = 0
Step-by-step explanation:
Using the formula for equation of a circle
(x - a)^2 + (y + b)^2 = r^2
(a, b) - the center
r - radius of the circle
Inserting the values given in the question
(-8,3) and r = 8
a - -8
b - 3
r - 8
[ x -(-8)]^2 + (y+3)^2 = 8^2
(x + 8)^2 + (y + 3)^2 = 8^2
Solving the brackets
( x + 8)(x + 8) + (y +3)(y+3) = 64
x^2 + 16x + 64 + y^2 + 6y + 9 = 64
Rearranging algebrally,.
x^2 + y^2 + 16x + 6y + 9+64 - 64 = 0
Bringing in 64, thereby changing the + sign to -
Therefore, the equation of the circle =
x^2 + y^2 + 16x + 6y + 9 = 0
The coefficient of y = 3
coefficient = the constant in front of a variable
Constant means that the number will not change.
hope this helps
The answer would be =<span>11/<span>20--Welcome , hopes this helps :P</span></span>
Answer: -20
Step-by-step explanation: Using the same expression except positive numbers, 4 x 5 = 20.
In this case, we can use this equation to find the product for the expression
4 x -5.
If 4 x 5 = 20, then 4 times -5 will also equal 20. However, since there is a negative factor in this expression, our answer will be negative causing our answer to be <u>-20.</u>