Please provide more of the question so I am able to answer, but I do know that H20 has 0 calories.
No, the correct answer is B. Physical change because the identity of the substance does not change.
For example, if you take a piece of paper and tear it in half you actually changed its property because now those pieces of paper have half the weight and and size that they did before you did anything. Now you know its a physical change because its still paper all you have done is change the physical appearance.
Hope this was helpful(;
Did you happen to find the answer yet? I've tried to find it, but I haven't succeeded yet
Answer:
Grass, trees, and flowers.
Explanation:
A producer converts the suns energy to make its own food, and a producer uses photosynthesis.
Answer:
Potassium
General Formulas and Concepts:
<u>Chem</u>
- Reading a Periodic Table
- Periodic Trends
- Ionization Energy - energy required to remove an electron from a given element
- Coulomb's Law
- Shielding Effect
- Z-effective and Forces of Attraction
Explanation:
The Periodic Trend for 1st Ionization Energy is increasing up and to the right. That means He would have the highest I.E and therefore take the most amount of energy to remove an electron.
Potassium and Gallium are both in Period 4. Potassium is element 19 and Gallium is element 31.
Potassium's electron configuration is [Ne] 4s¹ and Gallium's electron configurations is [Ne] 4s²3d¹⁰4p¹. Since both are in Period 4, they have the same number of core e⁻. Therefore, the shielding effect is the same.
However, since Gallium is element 31, it has 31 protons compared to Potassium, which is element 19 and has 19 protons. Gallium would have a greater Zeff than Potassium as it has more protons. Therefore, the FOA between the electrons and nucleus of Ga is much stronger than that of K. Thus, Ga requires <em>more</em> energy to overcome those FOA to remove the 4p¹ e⁻. Since K has less protons, it will have a smaller Zeff and thus less FOA between the e⁻ and nucleus, requiring <em>less</em> energy to remove the 4s¹ e⁻.
