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Sedbober [7]
3 years ago
13

What pressure, in atm, is exerted by 2.50 L of gas containing 1.35 mol at 320 K?

Chemistry
1 answer:
salantis [7]3 years ago
6 0

Answer:

Option A = 14.19 atm

Explanation:

Given data:

Volume of gas = 2.50 L

Number of moles of gas = 1.35 mol

Temperature of gas = 320 K

Pressure of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values in formula.

P × 2.50 L =  1.35 mol × 0.0821 atm.L/ mol.K×   320

P = 35.467 atm.L/ 2.50 L

P = 14.19 atm

Thus, option A is correct.

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Answer:

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Explanation:

In order to determine the mass of a given number of atoms of an element, identify the equalities between moles of the element and atoms of the element, and between moles of the element and its molar mass.

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mole atoms Ag=6.022xx10

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Molar mass of Ag =#"107.87 g/mol"#

Multiply the given atoms of silver by

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. Then multiply times the molar mass of silver.

4.6

×

10

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atoms Ag

×

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6 0
3 years ago
A block of ice is cooled from -0.5 degrees Celsius to -10.1 degrees Celsius. Calculate the temperature change, delta T, in degre
ss7ja [257]
Delta T= T final - T initial
Tfinal= -101.1 °C
Tinitial= -0.5 °C
•Delta T = -101.1°C - (-0.5°C)
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Kelvin= °C + 273
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Inessa05 [86]

Answer:

The answer is <u>applied research</u>

Explanation:

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