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Sedbober [7]
3 years ago
13

What pressure, in atm, is exerted by 2.50 L of gas containing 1.35 mol at 320 K?

Chemistry
1 answer:
salantis [7]3 years ago
6 0

Answer:

Option A = 14.19 atm

Explanation:

Given data:

Volume of gas = 2.50 L

Number of moles of gas = 1.35 mol

Temperature of gas = 320 K

Pressure of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values in formula.

P × 2.50 L =  1.35 mol × 0.0821 atm.L/ mol.K×   320

P = 35.467 atm.L/ 2.50 L

P = 14.19 atm

Thus, option A is correct.

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Balance the following reaction in KOH (under basic conditions). What are the coefficients in for C3H8O2 and KMnO4 in the balance
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Answer:

Coefficient of C_3H_8O_2=3

Coefficient of KMnO_4=8

Explanation:

We are given that  a reaction in which C_3H_8O_2 reacts with KMnO_4

We have to find the coefficient of each reactants in balanced reaction

3C_3H_8O_2(aq)+8KMnO_4(aq)\rightarrow 3C_3H_2O_4K_2(aq)+8MnO_2(aq)+2KOH+8H_2O

Coefficient is defined the constant  value multiplied with a reactant in a reaction.

Coefficient of C_3H_8O_2=3

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Coefficient of C_3H_2O_4K_2=3

Coefficient of MnO_2=8

Coefficient of H_2O=8

Coefficient of KOH=2

Hence, Coefficient of C_3H_8O_2=3 and coefficient of KMnO_4=8

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