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sdas [7]
3 years ago
15

A group of scientists at a space research organization is studying a newly discovered galaxy. How can they collect data about th

e galaxy?
A) Send space probes to the galaxy to take pictures
B) Use the internet to gather information about galaxies.
C) Send sound signals and wait for the signals to come back.
D) Observe photos of the galaxy taken by telescopes in space.
Chemistry
2 answers:
vova2212 [387]3 years ago
7 0

Answer:

(D)   Observe photos of the galaxy taken by telescopes in space.

Explanation:

The best way to collect data about the galaxy is to observe photos of the galaxy taken by telescopes in space. The galaxy is newly discovered, so information about it will be unavailable on the internet. Gathering information about galaxies in general will not help either. Sending space probes or sound signals would take a lot of time, perhaps even in light years

miss Akunina [59]3 years ago
6 0

The answer is D) Observe photos of the galaxy taken by telescopes in space.

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Can someone help me please??
Xelga [282]

41) Answer is: the average atomic mass of chromium is 52.056.

Ar(⁵⁰Cr) = 50.

ω(⁵⁰Cr) = 4.34% ÷ 100%.

ω(⁵⁰Cr) = 0.0434; relative abundance of chromium-50.

Average mass can calculate by summary of percentege of each isotope.

Ar(Cr) = Ar(⁵⁰Cr) · ω(⁵⁰Cr) + Ar(⁵²Cr) · ω(⁵²Cr) + Ar(⁵³Cr) · ω(⁵³Cr) + Ar(⁵⁴Cr) · ω(⁵⁴Cr).

Ar(Cr)= 50 · 0.0434 + 52 · 0.8379 + 53 · 0.095 + 54 · 0.0237.

Ar(Cr) = 2.17 + 43.571 + 5.035 + 1.280

Ar(Cr) = 52.056.

42) Chlorine has atomic number 17, it means it has 17 protons and 17 electrons.

Electron configuration of chlorine atom: ₁₇Cl 1s² 2s² 2p⁶ 3s² 3p⁵.

Chloride is negative ion of chlorine. Chloride is formed when chlorine gain one lectron.

Chloride anion has 17 protons and 18 electrons (like argon-noble gas).

The electron configuration for the chloride ion: ₁₇Cl⁻ 1s²2s²2p⁶3s²3p⁶.

43) Anwser is: the percent by mass of hydrogen in aspirin is 4.48%.

% calculate by atomic mass of element multiply number of that element in molecule divided by molecular mass of molecule.

Ar(H) = 1.008; the relative atomic mass of hydrogen atom.

Mr(C₉H₈O₄) = 9 · Ar(C) + 8 · Ar(H) + 4 · Ar(O).

Mr(C₉H₈O₄) = 180.157.

ω(H)= 8 · Ar(H) ÷ Mr(C₉H₈O₄) · 100%.

ω(H) = 8 · 1.008 ÷ 180.157 · 100%.

ω(H) = 4.48 %.

44) Balanced chemical reaction:

Cd(NO₃)₂ + 2NH₄Cl → CdCl₂ + 2NH₄NO₃.

This chemical reaction is double displacement reaction - cations (Cd²⁺ and NH₄⁺) and anions (NO₃⁻ and Cl⁻) of the two reactants switch places and form two new compounds.

Cd(NO₃)₂ is cadmium nitrate.

NH₄Cl is amonium chloride.

CdCl₂ is cadmium chloride.

NH₄NO₃ is ammonium nitrate.

4 0
4 years ago
For the reaction 2 HCl + Ca ( OH ) 2 ⟶ CaCl 2 + 2 H 2 O how many grams of calcium hydroxide, Ca(OH)2, are needed to react comple
kari74 [83]

Answer: 65.38g of Ca(OH)2 is needed

Explanation:

From The equation of reaction

2 HCl + Ca ( OH ) 2 ⟶ CaCl 2 + 2 H 2 O

NB: Molar mass of HCl= 1+35.5=36.5

Ca(OH)2= 74

From The stoichiometric equation

2mol of HCl(36.5×2=73) require 1mol of Ca(OH)2 (74g)

Hence 64.5g of HCl will require 64.5×74/73= 65.38g of Ca(OH)2

5 0
3 years ago
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti
gayaneshka [121]

Answer : The value of K for this reaction is, 2.6\times 10^{15}

Explanation :

The given chemical reaction is:

CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)

Now we have to calculate value of (\Delta G^o).

\Delta G^o=G_f_{product}-G_f_{reactant}

\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]

where,

\Delta G^o = Gibbs free energy of reaction = ?

n = number of moles

\Delta G^0_{(HCH_3CO_2(g))} = -389.8 kJ/mol

\Delta G^0_{(CH_3OH(g))} = -161.96 kJ/mol

\Delta G^0_{(CO(g))} = -137.2 kJ/mol

Now put all the given values in this expression, we get:

\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]

\Delta G^o=-89.4kJ/mol

The relation between the equilibrium constant and standard Gibbs, free energy is:

\Delta G^o=-RT\times \ln K

where,

\Delta G^o = standard Gibbs, free energy  = -89.4 kJ/mol = -89400 J/mol

R = gas constant  = 8.314 J/L.atm

T = temperature  = 30.0^oC=273+30.0=303K

K = equilibrium constant = ?

Now put all the given values in this expression, we get:

-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K

K=2.6\times 10^{15}

Thus, the value of K for this reaction is, 2.6\times 10^{15}

4 0
4 years ago
A chemical reaction was carried out three times. The mass of the product was 8.93 g for the first trial, 8.94 g for the second t
joja [24]

The three mass value measure are precise mass

<u>explanation</u>

precise mass is term use to describe data from experiment that have  been repeated several times. An experiment that yield tightly grouped  set of data it has a high precision.  8.93 , 8.94  and 8.92 are precise mass since they have repeated severally

6 0
4 years ago
As a human being, we are considered to be a ..... because we rely on other organism for food​
ryzh [129]
Heterotrophs i think :)

3 0
3 years ago
Read 2 more answers
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