Answer:
sin B= square root of 3/ 2
Cos B= 1/2
tan B= square root of 3/1
Sin C=1/2
cos C square root of 3/2
tan C= 1/square root of 3
Step-by-step explanation:
31 degrees, 31 degrees, 118 degrees
Step-by-step explanation:
Step 1 :
Let x be the measure of 2 angles of the given isosceles triangle with same measure
Let y be the measure of 3rd angle
So we have x + x + y = 180
Step 2 :
Given that the measure of 3rd angle of triangle is 25° more than three times the measure of either of the other two angles
So we have , y = 3 x + 25
Step 3:
Substituting for y in the first equation we have,
x + x + 3 x + 25 = 180
=> 5 x + 25 = 180
=> 5 x = 180-25 = 155
=> x = 155/5 = 31
Hence the 2 angles of the triangle are 31 degrees.
Step 4:
we have y = 3 x + 25
=> y = 3 * 31 + 25 = 118
Hence the 3rd angle of given triangle is 118 degrees
Answer:
Yes
Step-by-step explanation:
Because 9, 12, and 15 are Pythagorean triples
<span>The triangle on paper is 5 inches wide by 7 inches high.</span><span>
</span><span>
If 1 inch on paper is equal to 1.5 feet on paper, then you need to multiply all dimensions by 18 because 1.5 feet is equal to 18 inches and you are getting 18 inches on the real banner for every inch on the paper banner. </span><span>
5 * 18 = 90 inches from the base of the rear triangle.</span><span>
7 * 18 = 125 inches for the height of the rear triangle. </span><span>
</span><span>The area of the paper triangle will be 5 * 7 / 2 = 35/2 square inches.</span><span>
The area of the rear triangle will be 90 * 125 / 2 = 5625 square inches. </span><span>
regarding feet:
The base of the real banner will be 125/12 = 10.41666666....... feet.</span><span>
the height of the real banner will be 90 / 12 = 7.5 feet.</span><span>
the area of the real banner will be 5625 / 12^1 = 5625 / 144 = 39.0625 square feet.</span><span>
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