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a_sh-v [17]
3 years ago
6

Under the same conditions of temperature and pressure, which of the following gases would behave most like an ideal gas?Ne, N₂,

or CH₄? Explain.
Chemistry
1 answer:
malfutka [58]3 years ago
3 0

Answer:

Ne

Explanation:

Atomic number of Ne is 10.

Electronic configuration of Ne:

1s^2 2s^2 2p^6

Octet of Ne is complete . Element having complete octet are stable and behave ideal gas.

N_2 and CH_4 are reactive and hence, does not behave as ideal gas.

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True or False a chemical formula is a representation of the smallest unit of a compound?
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Answer:

true. I think

Explanation:

A chemical formula shows the atoms a molecule is made of.

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Which of he following compounds is always part of an aqueous solution
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Answer: Water because if we say aqueous it means it resembles water or related to water.

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What is the ground state electron configuration for B3+ ?
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Limiting Reactants—————-
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Answer:

21.8 grams.

Explanation:

Molar mass data from a modern periodic table:

  • Mg: 24.301;
  • O: 15.999.

How many moles of MgO will be produced if Mg is the limiting reactant?

Number of moles of Mg:

\displaystyle n = \frac{m}{M} = \frac{16.3}{24.301} = 0.670644\;\text{mol}.

The ratio between the coefficient of Mg and that of MgO is 2:2. Two moles of Mg will make two moles of MgO. 0.670644 moles of MgO will be produced if Mg is the limiting reactant.

How many moles of MgO will be produced if O₂ is the limiting reactant?

Number of moles of O₂:

\displaystyle n = \frac{m}{M} = \frac{4.33}{15.999} = 0.270642\;\text{mol}.

The ratio between the coefficient of O₂ and that of MgO is 1:2. One mole of O₂ will make two moles of MgO. 2\times 0.270642 = 0.541284\;\text{mol} of MgO will be produced if O₂ is in excess.

How many moles of MgO will be produced?

0.541284 is smaller than 0.670644. Only 0.541284 moles of MgO will be produced since O₂ will run out before all 16.3 grams of Mg is consumed.

What's the mass of 0.541284 moles of MgO?

Formula mass of MgO:

24.301 + 15.999 = 40.300\;\text{g}\cdot\text{mol}^{-1}.

Mass of 0.541284 moles of MgO:

m = n \cdot M = 0.541284\times 40.300 = 21.8\;\text{g}.

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What was technicalagy like in the past
V125BC [204]
Most of it was analog
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Read 2 more answers
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