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nekit [7.7K]
2 years ago
10

Potassium chlorate decomposes to form potassium chloride and oxygen according to the following

Chemistry
1 answer:
Tresset [83]2 years ago
8 0

Answer:

O 392 g

Explanation:

39.2 grams of oxygen (O2) can be produced.

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Using spectroscopic notation write the complete electron configuration for the fluorine atom. Using noble gas notation write the
prohojiy [21]

Explanation:

Flourine has atomic number of 9 and hence 9 electrons in its neutral state. The full electronic configuration is given as;

1s2 2s2 2p5

Carbon has atomic number of 6 and hence 6 electrons in it's neutral state. The noble gas notation as the following format;

[closest noble gas before the element] remaining electrons

The nearest noble gas to carbon is Helium, the noble gas notation is given as;

[He] 2s4

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3 years ago
When you jump-starts a car, what happens to the stored energy in the working battery? PLEASE ANSWER
Yuri [45]
The stored energy in the battery does not work anymore.
4 0
3 years ago
What is the Na+ concentration in each of the following solutions:
iren [92.7K]

Sodium Sulfate = Na2(SO4) meaning there are two ions of Na+ in one mole of Sodium Sulfate the M stands for Molarity, defined as Molarity = (moles of solute)/(Liters of solution), So if the Na2SO4 solution is 3.65M that means one Liter of has 3.65 moles of Na2SO4, the stoichiometry of Na2SO4 shows that there would be two Na+ ions in solution for every one Na2SO4.

Therefore if 3.65 moles of Na2SO4 was to dissolve, it would produce 7.3 moles of Na+, and since this is still a theoretical solution, we can assume 1 L of solution.

Finally we find [Na+] = 2*3.65 = 7.3M

Use the same logic for parts b and c




5 0
3 years ago
A. Electrons have a charge of_____
Dmitry [639]
Electrons: negative
Protons: positive
Neutrons: nuetral
5 0
3 years ago
Read 2 more answers
A student calculated the density of a sample of graphite to be 2.3 g/cm3. Show a numerical setup for calculating the student’s p
LUCKY_DIMON [66]

Answer:

Percent error = 1.5%

Explanation:

Given data:

Measured value of density of graphite = 2.3 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = [Measured value - Actual value / actual value] × 100

Actual/accepted value of density of graphite = 2.266 g/cm³

Now we will put the values:

Percent error = [2.3 g/cm³ - 2.266 g/cm³ / 2.266 g/cm³] × 100

Percent error = [0.034 g/cm³ / 2.266 g/cm³] × 100

Percent error = 0.015  × 100

Percent error = 1.5%

8 0
2 years ago
Read 2 more answers
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