You can use Heron's formula to do this
Area of triangle = sqrt[ s(s-a)(s-b)(s-c) ] where s = half the perimeter of the triangle =
1/2 * 13+5+9 = 13.5
so required area = sqrt [ (13.5)(13.5-13)(13.5-5)(13.5-9)]
= 16.1 square meters
X² + 5x - 24 = 0
x² - 3x + 8x - 24 = 0
x(x-3) + 8(x-3) = 0
(x+8)(x-3) = 0
x+8 = 0 or x-3 = 0
x = -8 x = 3
Answer: x=-8, x=3
Answer:
Its F(x)=-1/4x-1/4
Step-by-step explanation:
just took a quiz in class
Answer:
-20
Step-by-step explanation:
Just plug in 10 for x in the first equation.
y = -5 (10) + 30 = -50 + 30 = -20
Think of it as a fraction (14/20). If you multiply 20 by 5, you get 100. Whatever you do to the bottom, you have to do to the top. So 14 x 5 would be 70. The entire fraction would be 70/100 or 70%.
