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timurjin [86]
3 years ago
8

Which one of the following equations represents a circle with its center of origin?

Mathematics
1 answer:
babymother [125]3 years ago
3 0

Answer:

  • A) x² + y² = 5

Step-by-step explanation:

<u>The equation of the circle:</u>

  • (x - h)² + (y - k)² = r²

The center is (h, k)

<u>Wen the center is the origin we have, h = 0, k = 0:</u>

  • x² + y² = r²

The only equation in same format is the first one

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Right an Algebraic expression for 3 times X squared minus 4 times X
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3 times X squared minus 4 times X =


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3 years ago
Is it yes or no if yes can you please explain it
11111nata11111 [884]

Answer:

No, these triangles are not similar.

Step-by-step explanation:

Similar triangles have the same angle measures.

Knowing that the angles in a triangle add up to 180 degrees, find the missing angle, and you will see that the angles in the triangle are not congruent to each other, meaning that the triangles are not similar.

6 0
3 years ago
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One vegetable warehouse had 210 tons of potatoes, another one had 180 tons. 90 tons of potatoes were delivered to the first and
vivado [14]

Answer:

6 days

Step-by-step explanation:

The equation for first warehouse would be:

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The equation for 2nd warehouse would be:

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This means the first warehouse expression TIMES 1.2 would give us 2nd warehouse expression. Equating and solve:

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So it would require 6 days

4 0
3 years ago
A parabolà can be drawn given a focus of (7,9) and a
NeTakaya

from the provided focus point and directrix, we can see that the focus point is above the directrix, meaning is a vertical parabola and is opening upwards, thus the squared variable will be the "x".

keeping in mind the vertex is half-way between these two fellows, Check the picture below.

\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\bf \begin{cases} h = 7\\ k = 7\\ p = 2 \end{cases}\implies 4(2)(y-7)=(x-7)^2\implies 8(y-7)=(x-7)^2 \\\\\\ y-7=\cfrac{1}{8}(x-7)^2\implies \boxed{y=\cfrac{1}{8}(x-7)^2+7}

6 0
4 years ago
Find the product of 20x9x5
Anestetic [448]
20 times 9 times 5 equals 900
5 0
3 years ago
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