Sqare √113
113
10^2=100, so √100=10
11^2=121 so √121=11
√100<√113<√121
so therfor
10<√113<11
it is between 10 and 11
Answer:
3(3x-2)
Step-by-step explanation:
this is factoring 3 out of 9x-6
Answer:
All numbers less than 2 or or
Step-by-step explanation:
Given that:
Number is added to itself is less than the number subtracted from 6.
To find:
All such numbers.
Solution:
Let the number be .
Here, an inequality will be made.
When solved, it might give more than one answers.
As per the question statement, let us write the inequality.
Number added to itself
Number subtracted from six =
As per question:
So, the answer is:
All numbers less than 2 or or .
Answer:
2.5
Step-by-step explanation:
The computation of the XW is shown below
As triangle UVX is a right angle
So
VU^2 = XU^2 - VX^2
VU^2 = 15.7^2 - 8.5^2
VU^2 = 246.49 - 72.25
VU^2 = 174.24
VU = 13.2
As VU = WX because of same point tangent
NOw XW is
= UX - UW
= 15.7 - 13.2
= 2.5