Step-by-step explanation:
h(x) = (f-g) (x) = 3x²+4x-10- 7x²+x-4
= -4x²+5x-14 (option D)
Using proportions and the information given, it is found that:
- The class width is of 14.375.
- The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
- The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.
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- Minimum value is 19.
- Maximum value is of 134.
- There are 8 classes.
- The classes are all of equal width, thus the width is of:
-------------------------
The intervals will be of:
19 - 33.375
33.375 - 47.750
47.750 - 62.125
62.125 - 76.500
76.500 - 90.875
90.875 - 105.250
105.250 - 119.625
119.625 - 134.
- The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
- The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.
A similar problem is given at brainly.com/question/16631975
I am happy to help... but <span>Please be more specific with your question.
</span>
Answer:
a. 20h + 8
Step-by-step explanation:
-2(-7h-4) + 6h = 14h + 8 + 6h = 20h + 8
<em>Answer:</em>
Complete proof is written below.
Facts and explanation about the segments shown in question :
- As BC = EF is a given statement in the question
- AB + BC = AC because the definition of betweenness gives us a clear idea that if a point B is between points A and C, then the length of AB and the length of BC is equal to the length of AC. Also according to Segment addition postulate, AB + BC = AC. For example, if AB = 5 and BC= 7 then AC = AB + BC → AC = 12
- AC > BC because the Parts Theorem (Segments) mentions that if B is a point on AC between A and C, then AC > BC and AC>AB. So, if we observe the question figure, we can realize that point B lies on the segment AC between points A and C.
- AC > EF because BC is equal to EF and if AC>BC, then it must be true that the length of AC must greater than the length segment EF.
Below is the complete proof of the observation given in the question:
<em />
<em>STATEMENT REASON </em>
___________________________________________________
1. BC = EF 1. Given
2. AB + BC = AC 2. Betweenness
3. AC > BC 3. Def. of segment inequality
4. AC > EF 4. Def. of congruent segments
<em />
<em>Keywords: statement, length, reason, proof</em>
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