According to the Law of conservation of mass, the grams of oxygen formed are A) 0.7 g.
Explanation:
According to the Law of conservation of mass, the total mass of the products in a chemical reaction must be equal to the total mass of the reactants.
In this problem, the chemical reaction is:
where
is the mercuric oxide
Hg is the liquid mercury
O is the oxygen
We have the following data:
(mass of mercuric oxide)
(mass of liquid mercury)
Since the mass of the products must be equal to the mass of the reactant (the HgO), we can find the mass of the oxygen produced:
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Answer:
The period of the orbit is 12163.649 seconds.
Explanation:
What quantity are you looking for? I'll assume it's the orbital period.
The period, P, of an orbit in seconds is found from
P = 2π √[a³/(GM)]
where
a = the semimajor axis of an elliptical orbit, or the radius of a circular orbit
G = 6.67428e-11 m³ kg⁻¹ sec⁻²
M = the sum of the masses of Mars and the satellite
The mass of the satellite is presumably negligible.
M = 6.4191e+23 kg
a = 1.6 Rmars = 1.6 (3.397e+6 meters) = 5435200 m
Therefore,
P = 12163.649 sec
Answer:
75 kgm/s
Explanation:
Impulse: This can be defined as the product of mass and change in velocity. The S.I unit is kgm/s.
From the question,
I = m(v-u)................... Equation 1
Where I = impulse, m = mass, v = final velocity, u = initial velocity.
Let the direction of the initial velocity be the positive direction.
Given: m = 5 kg, v = -10 m/s (bounce off), u = 5 m/s.
Substitute into equation 1
I = 5(-10-5)
I = 5(-15)
I = -75 kgm/s.
The negative sign tells that the impulse act in the same direction as the final velocity of the ball
Hence,
I = 75 kgm/s
Since the mirror is plane, the image will be formed behind the mirror. The distance will be the same as that of the distance of the object from the mirror and the height will just be the same.
So, Ruff's image will be 3 m behind the mirror and 50 cm tall.