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CaHeK987 [17]
3 years ago
10

A 275-kilogram object starts from rest and accelerates on level ground up to a speed of

Physics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

Explanation:

a )

mass m = 275 kg , final velocity v = 41 m/s

distance,  s = 49.3 m

acceleration a = ?

v² = u² + 2as

41² = 2 a x 49.3

a = 17.05 m/s²

time t = v - u / a

t = 41 / 17.05

= 2.4 s

b )

force = mass x acceleration

= 275 x 17.05

= 4688.75 N

c ) maximum range = v² / g

= 41²/9.8

= 171.5 m

height ( maximum )

v² sin²45 / 2g ( at angle of projectile of 45 , range and height is maximum.)

= 41²/ 2 x 9.8

= 85.76 m

d )

Let the angle be θ

height h = v² sin²θ / 2g

50 = 41² sin²θ /2g

sin²θ  = .58

sinθ = .76

50°.

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5) Find the initial velocity for a 700 kg car that
Serhud [2]

Answer:

Δv = 12 m/s, but we are not given the direction, so there are really an infinite number of potential solutions.

Maximum initial speed is 40.6 m/s

Minimum initial speed is 16.6 m/s

Explanation:

Assume this is a NET impulse so we can ignore friction.

An impulse results in a change of momentum

The impulse applied was

p = Ft = 1400(6.0) = 8400 N•s

p = mΔv

Δv = 8400 / 700 = 12 m/s

If the impulse was applied in the direction the car was already moving, the initial velocity was

vi = 28.6 - 12 = 16.6 m/s

if the impulse was applied in the direction opposite of the original velocity, the initial velocity was

vi = 28.6 + 12 = 40.6 m/s

Other angles of Net force would result in various initial velocities.

5 0
3 years ago
A uniformly charged, thin ring has radius 15.0 cm and total charge +24.0 nC. An electron is placed on the ring’s axis a distance
djyliett [7]

Answer:

A. The electron will begin to move along the axis, towards the centre and the instantaneous velocity because the force acting on it depends largely on acceleration and x until it reaches maximum velocity at centre.

B. Veloctiy (Vb) = 1.66m/s

Explanation:

Given the following data

x(a) = 0.3m

x(b) = 0

q = 1.6×10^-19

Q = 24nc

r = 0.15m

Required: the motion of the electron and the velocity (Vb)

1. At point A the electron will begin to move along the axis from point A to point B, the magnitude of the electric field will change while moving which depends on that and this will produce instantaneous force which will later change and the acceleration will change too while moving, the velocity would reach maximum value at point B

2. Potential energy and kinetic energy are given by

U(a) + K(a) = U(b) + K(b). . .1

Initial P.E and K.E are given as

U(a) = kQ/√x²(a) + a2

By substitution, we have

U(a) = 9×10^9 × (-1.9×10^-19)×24×10^-9/√(0.15)²+(0.3²)

U(a) = -1.03×10^-16

Final P.E and K.E are given as

U(b) = KQ/√x²(b) + a2

By substitution, we have

U(b) = 9×10^9×(-1.9×10^-19)×24×10^-9/√(0.15)²+(0)²

U(b) = -2.3×10^16

3. By substitution into equation 1 becomes

-1.03×10^-6 - 2.3×10^-16 + MV²(b)/2

V(b) = √2×1.27×10^-16/9.1×10^31

V(b) = 1.66×10^7m/s

4 0
4 years ago
A student boils water in a can and puts the hot can carefully in very icy water. The can immediately crushes due to the change i
hammer [34]

Answer:

By elimination I know it's not CGL and I know it's not Charle's Law.

Gay-Lussac's law states the pressure of a a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant. I think it's Gay-Lussac's Law.

Boyle's law states that pressure of a gas tends to increase as the volume of the container decreases which I got from a google search because I didn't know what it was.

CGL is the combined formula of all of these laws by the way

Charle's law is just gas expands when heated.

Gay-Lussac's is the best answer choice in my opinion

8 0
4 years ago
At the top of the first hill you have the ________ Gravitational Potential Energy
lana66690 [7]

Answer:

increase.

Explanation:

as you being your trip dow hill you increase your speed resulting a transformation from GPE to KE.

6 0
2 years ago
A grasshopper jumps and accelerates at 4.5 m/s2. If its legs exert a force of 0.062 N during the jump, what is the mass of the g
Naily [24]

Answer:

0.014 kg

Explanation:

trust me its right i took the assessment and got 100%.  :)

5 0
3 years ago
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