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____ [38]
4 years ago
14

The following represents a process used to assemble a chair with an upholstered seat. stationsa, b, and c make the seat; station

s j, k, and l assemble the chair frame; station x is wherethe two subassemblies are brought together; and some fi nal tasks are completed in stations yand z. one worker is assigned to each of the stations. generally, no inventory is kept anywherein the system, although there is room for one unit between each of the stations that might beused for a brief amount of time.bcakljx y zgiven the following amount of work in seconds required at each station:a 38 j 32 x 22b4. the following represents a process used to assemble a chair with an upholstered seat. stationsa, b, and c make the seat; stations j, k, and l assemble the chair frame; station x is wherethe two subassemblies are brought together; and some fi nal tasks are completed in stations yand z. one worker is assigned to each of the stations. generally, no inventory is kept anywherein the system, although the
Physics
1 answer:
Mekhanik [1.2K]4 years ago
7 0

There are three questions here:


A. The possible daily output of this process if there is 8 processing time each day?


the time it takes to assemble a chair in seconds = A + B + C + J + K + L + X + Y + Z  

which is equal to = 38 + 34 + 35 + 32 + 30 + 34 + 22 + 18 + 20 =263 per chair



Processing hours = 8 hours x 60 minutes x 60 seconds

= 8 x 60 x 60


= 480 x 60 = 28,800 seconds is available in an 8 hr day.



28,800 / 263 =109.5057034220532


Therefore, It is possible to make 109 chairs in an 8 hour day.



B. Given your output rate in above, what is the efficiency of the process?


The time it takes to assemble a chair in seconds = A+ B + C + J + K + L + X + Y + Z.


= 34 + 34 + 34 + 30 + 30 + 30 + 22 + 18 + 20 = 252.6315789473684 per chair


A total of 252 per chair


Processing hours = 8 hours x 60 minutes x 60 seconds


= 8 x 60 x 60


= 480 x 60 = 28,800 seconds is available in an 8 hour day


= 28,000 / 252 = 114.2857142857143114 chairs


= 109/114 x 100 = 95.6140350877193


Therefore, the efficiency of making the chair is 95.61%


C. What is the flow time of the process?


Flow time is the period that it takes a completed chair to flow through the process from the beginning assemblage step to the last step. Take note that ABC and JKL are parallel legs in the process, and as a result both do not include to flow time to the procedure. In addition, Flow time comprises both pass time and run time at each position in the procedure.

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3 years ago
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7 0
3 years ago
Find the value of T1 if 1 = 30°, 2 = 60°, and the weight of the object is 139.3 newtons.
Lelechka [254]

Answer:

Option A (69.56 newtons) is the appropriate solution.

Explanation:

According to the question,

On the X-axis,

⇒ T_1Cos30^{\circ}-T_2Cos60^{\circ}=0

or,

    T_1Cos 30^{\circ}=T_2Cos60^{\circ}

On substituting the values, we get

      T_1\times \frac{\sqrt{3} }{2}=T_2\times \frac{1}{2}

      T_1\times \sqrt{3} =T_2....(equation 1)

On the Y-axis,

⇒ T_1Sin30^{\circ}+T_2Sin60^{\circ}=139.3 \ N

                        \frac{T_1}{2} +\frac{\sqrt{3} }{2} =139.2 \ N

                    T_1+\sqrt{3}T_2=139.2\times 2

From equation 1, we get

           T_1+\sqrt{3}\times \sqrt{3}T_1 =278.4 \ N

                        T_1+3T_1=278.4 \ N

                                4T_1=278.4 \ N

                                  T_1=\frac{278.4}{4}

                                       =69.6 \ N  

6 0
3 years ago
An object is moving with an initial velocity of 19 m/s.It is then subject to a constant acceleration of 2.5 m/s for 15s.How far
bija089 [108]

Answer:

566.3 m

Explanation:

The distance travelled by the object can be found by using the SUVAT equation:

d=ut+\frac{1}{2}at^2

where

u is the initial velocity

t is the time

a is the acceleration

For the object in this problem:

u = 19 m/s

a = 2.5 m/s^2

Substituting t = 15 s, we find the distance travelled:

d=(19)(15)+\frac{1}{2}(2.5)(15)^2=566.3 m

7 0
4 years ago
True Or False? The tendency for an object in motion to remain in motion is called orbital speed.
Harlamova29_29 [7]

The correct answer to the question is False i.e the tendency of an object in motion to remain in motion is not called the orbital speed.

EXPLANATION:

Before going to answer this question, first we have to understand Newton's first laws of motion.

As per Newton's first laws of motion, every body continues to be in state of rest or of uniform motion in a straight line unless and until it is compelled by some external unbalanced forces.

Hence, as long as no unbalanced force is acting on a moving object, it will be in motion. This tendency of a moving object to be in motion is called inertia of motion of the body.

Inertia of motion is the property of the body by virtue of which a moving body always tries to be in motion.

Hence, the tendency of an object in motion to remain in motion is not called as the orbital speed.

7 0
4 years ago
Read 2 more answers
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