Answer:
Fgparallel = 170N
Explanation:
Acting down the incline would be the paralell force. The Force of gravity on an incline for the parallel portion is mgsinθ.
Fg parallel = mgsinθ
mg is 289.9, as that is the weight. θ is 35.9
Fgpar = 289.9sin35.9
Fgparallel = 170N
The answer is
2.5 N
B
this needs to be 20 letters long so this part doesn't matter
Answer:
electrostatic force
Explanation:
Electrostatic force is the force that exists between electric charges on stationary charged bodies
As per the question the distance of venus from sun is given as 0.723 AU
We have been asked to calculate the time period of the planet venus.
As per kepler's laws of planetary motion the square of time period of planet is directly proportional to the cube of semi major axis. mathematically

⇒
where is k is the proportionality constant
We may solve this problem by comparing with the time period of the earth . We know that time period of earth is 365.5 days
Hence
The distance of sun from earth is taken as 1 AU i.e the mean distance of earth from sun
Hence 
The distance of venus from sun is 0.723 AU i.e
From keplers law we know that-
⇒
Putting the values mentioned above we get-

⇒
⇒
Hence the time period of venus is 224.388352752710 days
Answer:
a

b

Explanation:
From the question we are told that
The initial position of the particle is 
The initial velocity of the particle is 
The acceleration is 
The time duration is 
Generally from kinematic equation

=> 
=> 
Generally from kinematic equation

Here s is the distance covered by the particle, so

=> 
Generally the final position of the particle is

=> 
=> 