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coldgirl [10]
2 years ago
15

A force of 10 N acts on a mass of 5 kg producing an acceleration of 1.5 m/s2. What is the magnitude of

Physics
1 answer:
yulyashka [42]2 years ago
5 0

The answer is

2.5 N

B

this needs to be 20 letters long so this part doesn't matter

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Object 1 has a momentum of 10 kg m/s and Object 2 has a momentum of 25 kg m/s. Will it be easier to change the direction of move
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I think its object 1

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A fire is burning in a fireplace. Where is the radiation?
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Looking straight downward into a rain puddle whose surface is covered with a thin film of gasoline, you notice a swirling patter
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Answer:

 

Explanation:

Point beneath you forms a beautiful iridescent green

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Wavelength of Green light is \lambda =540\ nm

Here light first traverse from air(n=1) to gasoline , it reflects from  front surface of gasoline(n=1.38) so it suffers a phase change. After this light reflect from rear surface of gasoline and there is a decrease in refractive index(n=1.38 to n=1.33), so there is no phase change occurs .

For constructive interference

2t=(m+\frac{1}{2})\cdot \frac{\lambda }{n}

here t= thickness of gasoline film

n=refractive index

for m=0

t=\frac{\lambda }{4n}

t=\frac{540}{4\times 1.38}

t=97.82\approx 98\ nm                                                      

4 0
3 years ago
A marshmallow is dropped from a 5.71 meter high pedestrian bridge, and 0.921 seconds later, it lands right on the head of an uns
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let the height of the person with marshmallow on her head be "h"

consider the motion of the marshmallow after it is dropped from bridge.

Y₀ = initial position of the marshmallow above the ground = 5.71 m

Y = final position of marshmallow on head of person = h

v₀ = initial velocity of the marshmallow = 0 m/s

a = acceleration due to gravity = - 9.8 m/s²

t = time of travel for marshmallow = 0.921 sec

Using the kinematics equation

Y = Y₀ + v₀ t + (0.5) a t²

inserting the values

h = 5.71 + 0 (0.921) + (0.5) (-9.8) (0.921)²

h = 5.71 - 4.16

h = 1.55 m

5 0
3 years ago
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