Answer:
944.12 J
Explanation:
To solve for the energy change we use the equation Q=mc(Delta)t
Let's identify the variables we have:
m (mass) = 49.2 g
c (specific heat) = .4494
delta t (change in temp.) = final - initial = 58.9-16.2 = 42.7 degrees Celsius
Q= (49.2)(.4494)(42.7)
= 944.12 J
The molecules of a solid is compactly arranged. It is made up of repeating blocks called unit cells. The density of a unit cell is:
ρ = nA/VNₐ
where
n is the number of atoms per unit cell
A is the atomic weight of solid
V is the volume of unit cell
Na is Avogadro's number (6.022×10²³)
For a face-centered cubic unit cell, there are 4 atoms (n=4). The volume of the unit cell follows the formula of the cube, s³. The atomic weight of gold is 197 g. So, the solution is as follows:
ρ = (4 atoms)(197 g/mol)(1 kg/1000 g)/(407×10⁻¹² m)³(6.022×10²³ atoms/mol)
ρ = 19,408.5 kg/m³
Answer:
V(NH₃(g)) at STP = 0.8928 Liters ≅ 0.9 Liter (1 sig. fig)
Explanation:
Given 340g NH₃(g) => ?Volume at STP
Convert grams to moles by dividing by formula wt of ammonia
= 340g/17g/mole = 20 moles
1 mole of any gas at STP conditions (0°C, 1atm) occupies 22.41 Liters
∴ 20 moles NH₃(g) => 20moles/22.4Liters/mole
= 0.8928 Liters ≅ 0.9 Liter (1 sig. fig)
The answer could either be C or A.
they are different form of energy movement