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nekit [7.7K]
3 years ago
11

Brass is an example of a(n):

Chemistry
2 answers:
kogti [31]3 years ago
7 0

Answer:

homogeneous mixture or solid solution

Explanation:

A mixture is said to be a substance containing two or more substances that are not chemically combined together. A mixture can be easily separated to it original components.

Mixture are not chemically bonded together .  An homogeneous mixture is a mixture that is uniformly mixed together . example is air.

An heterogeneous mixture is a mixture is such that the components can be  separated from each other.

Brass is an homogeneous mixture  . Most Alloys of metals are  mixture example are Brass, steel and solder. Brass combines two different metal like zinc and copper to form brass. The mixture can be easily separated to their components elements and are not chemically bonded.  

Brass can also be regarded as a solid solution which involve zinc or other metals(solute) dissolve in a solvent(copper). The best option is a solution.

pogonyaev3 years ago
4 0
I believe the correct answer from the choices listed above is the third option. Brass is an example of a solution. Brass<span> is a homogeneous </span>mixture<span> of copper and zinc in which the concentration of zinc and copper is the same throughout the entire </span>mixture making it a solid solution.
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<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

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So, the mean activity coefficient is 0.78.

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