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Dvinal [7]
3 years ago
9

A gas has a volume of 5.00 L at 20.0oC. If the gas is compressed to 4.0 L, what is the new temperature of the gas in Kelvin?

Chemistry
1 answer:
Tatiana [17]3 years ago
8 0

Answer: 234.4K

Explanation:

Given that,

Original volume of gas (V1) = 5.00 L

Original temperature of gas (T1) = 20.0°C

[Convert 20.0°C to Kelvin by adding 273

20.0°C + 273 = 293K]

New volume of gas (V2) = 4.0L

New temperature of gas (T2) = ?

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

5.00L/293K = 4.0L/T2

To get the value of T2, cross multiply

5.00L x T2 = 293K x 4.0L

5.00L•T2 = 1172L•K

Divide both sides by 5.00L

5.00L•T2/5.00L = 1172L•K/5.00L

T2 = 234.4K

Thus, the new temperature of the gas is 234.4 Kelvin

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Answer: C. K_a would increase and pK_a would decrease.

Explanation:

HA\rightleftharpoons H^++A^-

initially conc.       c       0         0

At eqm.  c(1-\alpha)   c\alpha      c\alpha

The expression for dissociation constant is,

K_a=\frac{c\alpha\times c\alpha}{c(1-\alpha)}

for weak acid, \alpha is very very small , the expression will be,

K_a=\frac{c^2\alpha^2}{c}=c\alpha^2

K_a=c\alpha^2As k_a is directly proportional to concentration, the value of K_a would increase on increasing the concentration.

pK_a=log\frac{1}{K_a}

Thus if K_a would increase, pk_a would decrease.

8 0
3 years ago
how is the arrangement of molecules in a dense object different than arrangement by molecule in a less dense object
solmaris [256]

Answer:

The molecules in a dense object are tightly packed together

Explanation:

This happens because the closer molecules are the denser the object is, however, if they get too close it can be a very disastrous result and the compound becomes very unstable. Hope I could help! :)

7 0
4 years ago
In caves, dripping groundwater containing calcium bicarbonate can form stalactites and stalagmites. When the water is exposed to
Ksivusya [100]
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5 0
3 years ago
You are a NASCAR pit crew member. Your employer is leading the race with 20 laps to go. He just finished a pit stop and has 5.0
jek_recluse [69]

Answer:

Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

Explanation:

Density = mass / volume

Density of fuel = 700 g/ 1 gal

Therefore, the mass of fuel in 1 gallon = 700 g

The driver has 5.0 gallons of fuel in the tank.

The mass of 5.0 gallons of fuel = 5 × 700 = 3500 g of fuel

Equation of the combustion of fuel, C₅H₁₂ is given below:

C₅H₁₂ + 8 O₂ ---> 6 H₂O + 5 CO₂

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Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

7 0
3 years ago
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cestrela7 [59]
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Hope this helps!

5 0
3 years ago
Read 2 more answers
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