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3 years ago

A gas has a volume of 5.00 L at 20.0oC. If the gas is compressed to 4.0 L, what is the new temperature of the gas in Kelvin?

Chemistry

1 answer:

Tatiana [17]3 years ago

8 0

Answer: 234.4K

Explanation:

Given that,

Original volume of gas (V1) = 5.00 L

Original temperature of gas (T1) = 20.0°C

[Convert 20.0°C to Kelvin by adding 273

20.0°C + 273 = 293K]

New volume of gas (V2) = 4.0L

New temperature of gas (T2) = ?

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

5.00L/293K = 4.0L/T2

To get the value of T2, cross multiply

5.00L x T2 = 293K x 4.0L

5.00L•T2 = 1172L•K

Divide both sides by 5.00L

5.00L•T2/5.00L = 1172L•K/5.00L

T2 = 234.4K

Thus, the new temperature of the gas is 234.4 Kelvin

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3 years ago

An element has three stable isotopes with masses of 27.977 amu, 28.976 amu, and 29.973 amu. the heavier two isotopes have an abu

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Check attached file for solution.

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3 years ago

PLEASE HELP ASAP!

choli [55]

Answer:

$\large \boxed{\text{D. 710 g}}$

Explanation:

1. Calculate the molar mass of Na₂SO₄

$\begin{array}{ccc}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 23 & 46\\\text{1S} & 32 & 32\\\text{4O}&16 & 64\\&\text{TOTAL =} & \mathbf{142}\\\end{array}$

The molar mass of Na₂SO₄ is 142 g/mol.

2. Calculate the moles of Na₂SO₄

$\text{Moles of Na$_{2}$SO}_{4} = \text{2.5 L solution} \times \dfrac{\text{2.0 mol Na$_{2}$SO}_{4}}{\text{1 L solution}} = \text{5.0 mol Na$_{2}$SO}_{4}$

3. Calculate the mass of Na₂SO₄

$\text{Mass of Na$_{2}$SO}_{4} = \text{5.0 mol Na$_{2}$SO}_{4} \times \dfrac{\text{142 g Na$_{2}$SO}_{4}}{\text{1 mol Na$_{2}$SO}_{4}} = \text{710 g Na$_{2}$SO}_{4}\\\\\text{You need } \large \boxed{\textbf{710 g}} \text{ of Na$_{2}$SO}_{4}$

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3 years ago

Potassium chlorate decomposes into potassium chloride and oxygen gas. How many grams of oxygen are produced when 1.06 grams of p

kifflom [539]

The amount of oxygen that are produced when 1.06 grams of potassium chlorate decompose completely is 0.64 grams.

<h3>What is the relation between mass & moles?</h3>

Relation between the mass and moles of any substance will be represented as:

n = W/M, where
W = given mass
M = molar mass

Moles of potassium chlorate = 1.66g / 122.5g/mol = 0.0135mole

Given chemical reaction is:

2KClO₃ → 2KCl + 3O₂

From the stoichiometry of the reaction, it is clear that:

2 moles of KClO₃ = produces 3 moles of O₂

0.0135 moles of KClO₃ = produces (3/2)(0.0135)=0.02 moles of O₂

Mass of oxygen = (0.02mol)(32g/mol) = 0.64 g

Hence produced mass of oxygen is 0.64 grams.

To now more about mass & moles, visit the below link:
brainly.com/question/18983376

#SPJ1

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2 years ago