Y= 1x is the correct answer
You have to know a great deal more about where Q and Q' are before you can say much of anything. The problem is listed a s a middle school problem so you are likely permitted to go by the way it looks, but that is not a habit that I would continue using.
So if the triangles SQR and S'Q'R' are congruent, and if they are orientated exactly the same way which means that the distance between QQ' and RR' is a constant (and those are big ifs), then you can claim that QQ' is parallel to the other two lines. Is it the same length as the other two? Again, you obtained the other two by measurement. It looks like SQR and S'Q'R' are equilateral and if that is correct then yes they lengths are all equal. But your marker could do just about anything with this question.
If you have a person marking this, talk it over with them. I say QQ' is equal and parallel to the other two, but don't be surprised if it is wrong.
Q19) the answer is 4 as 1 kg = 1000 and 1000 divided by 250 is 4
Q20) 3kg as 225 x 2 = 500 plus 800 x 3 = 2400 and 500 + 2400 = 2900 which is closer to 3000g which is 3kg
Q21) the blue and gold macaw as 1kg = 1000g and 800g is closet to that
From the information given, the differential equation will be di/dt = (E - Ri) / L.
<h3>How to calculate the differential equation</h3>
From the information given, we can set up the differential equation as:
-E(t) = Ldi(t)/Dr + Ti(t) = 0.
Here, i(t) = I
E(t) = E
Therefore, this will be:
= -E + Ldi/dt + Ri = 0
We'll now solve for di/dt
Ldi/dt = E - Ri
di/dt = (E - Ri) / L
Learn more about differential equations on:
brainly.com/question/1164377
