Let x be the volume (liters) of pure (at 100%) acid needed
Let y be the volume (liters) of the other acid (at 10%) needed
The final solution will be:
a) x+ y = 63 liters, AND their respective concentration in acid: is
100% x & 10% :y that will generate 63 liters at 20%
b) x +0.1 y = 63x 0.2 = 12.6
Let's solve this system of 2 equations:
x + y =63
x + 0.1 y = 12.6
Solving it will give you:
x= 7 liters at 100%
y = 56 liters at 10%
Since the x's both are to a power and have exponents outside of the parenthesis, we multiply the inner exponent by the outer exponent.
x^-150 / x^-144
Then, we need to move the bottom term to the top so that we have no negative exponents. Now, we are technically subtracting, but subtracting a negative is the same thing as adding.
x^(-150 + 144)
x^-6
Hope this helps!
I thin there are in 48 in 3 gallons
Answer:
I believe your answer is correct. Though I'm not sure if the first picture is right too.
Step-by-step explanation:
