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kondaur [170]
3 years ago
14

What real world situation models this equation y=1/20x

Mathematics
1 answer:
garri49 [273]3 years ago
3 0
This is a proportional relationship. So any example that shows as x increases, y decreases.
A real life example would be where 
x=time i let the pool drain
y=amount of water left over

As I let the time I let the pool drain increase, the amount of water left in the pool decreases.
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What is the force acting on a 16 kg object accelerating at 2.0 m/s2
alexira [117]

Answer:

32 n

Step-by-step explanation:

I had the same problem but I used a net force calculator the formula is F=MA so it would be 32=16/2.0 :)

6 0
3 years ago
What does x equal in this problem
IgorLugansk [536]

Answer:

i think 9

Step-by-step explanation:

45/5 is 9 so hope thus helps

6 0
3 years ago
Read 2 more answers
What is the slope intercept equation of the line below?
valentina_108 [34]
The answer is letter D
6 0
2 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
83 POINTS FOR WHOEVER ANSWERS THESE QUESTIONS:<br><br> PICTURES
motikmotik

Answer:

y=sqrt((x+a)/-2b))

F=(5/9)C+32

Can't read the rest

Step-by-step explanation:

-2by^2=x+a

y^2=(x+a)/-2b

y=sqrt((x+a)/-2b))


F-32=(5/9)C

F=(5/9)C+32 (The actual Fahrenheit-Celcius formula)

NOTE: The other pictures cannot be opened.



7 0
3 years ago
Read 2 more answers
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