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bulgar [2K]
3 years ago
10

In a survey of 800 students,

Mathematics
1 answer:
Lunna [17]3 years ago
8 0

The bar graph shows in the attachment bases on frequency distribution equation for Lunch is 68:22:10 which mean the equation is 68x+22y+10 is the combined information.

Step-by-step explanation:

  • Column lunch and row had Pizza,Hamburger and Sloppy joe.
  • The total 548,173 and 79 total to 800 students.
  • Creating a bar graph series name is lunch and series value is pizza....
  • hamburgers and sloppy joes.
  • Frequency distribution basis on percentage involves...
  • Number of categories/ Total number of students.
  • 68:22:10 so the distribution has about 68 percent of people....
  • Eat pizza more than hamburger and sloppy joes.
  • Horizontal axis has about Pizza,Hamburger and Sloppy joes.

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goblinko [34]

option 4 .x<11 is the correct answer

4 0
3 years ago
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dmitriy555 [2]

Answer:

+ + + + += + + + + +

Step-by-step explanation:

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Masteriza [31]
The unit rate would be 11/2. Hope this helped.
3 0
3 years ago
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me
Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is P(X = 2). So:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

3 0
3 years ago
Translate this phrase into an algebraic expression.
saul85 [17]
ANSWER: 2j-61
j = Jenny's age
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3 years ago
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