I need to answer two questions to ask again sorry
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We can write the system in the following form:
![\left[\begin{array}{cccc}5&-4&4&2\end{array}\right] \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right] =b](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%26-4%264%262%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx_1%5C%5Cx_2%5C%5Cx_3%5C%5Cx_4%5Cend%7Barray%7D%5Cright%5D%20%20%3Db)
The above system is equivalent to the following equation:

Of course, the above system has solution for any values of b since there is one equation and four variable, there is infinite number of solution each time.
so, the thousandth place is (EXAMPLE THIS IS: 0.00<u>1</u>) in this case, the 9 is in the thousandths place, and because the number to the right is greater than five, the answer is: 0.020, because you would round <u>UP</u>.
Answer: 5(√3-1) unit.
Step-by-step explanation:
Since, By the below diagram,
For triangle BDC,
We can write,

⇒ 
⇒ 
⇒ 
⇒ 
Now, In triangle ADC,

⇒ 
⇒ 
⇒ 
⇒ 
⇒ 