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2 years ago

Select the correct answer.

Chemistry

1 answer:

ser-zykov [4K]2 years ago

3 0

Answer:

I think the answer would be option d.

hope it helps.

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You prepare a 2nd solution (solution B) by pipetting 10.00 ml of your 1st solution (solution A) into a 50.00 ml volumetric flask

elena-14-01-66 [18.8K]

Answer:

Concentration solution A was 0.5225 M

Explanation:

10.00 mL of solution A was diluted to 50.00 mL and yields 50.00 mL of solution B

According to laws of dilution- $C_{A}V_{A}=C_{B}V_{B}$

where, $C_{A}$ and $C_{B}$ are concentration of solution A and B respectively

$V_{A}$ and $V_{B}$ are volumes of solution A and B respectively

Here $C_{B}$ = 0.1045 M, $V_{B}$ = 50.00 mL and $V_{A}$ = 10.00 mL

Hence, $C_{A}=\frac{C_{B}V_{B}}{V_{A}}=\frac{(0.1045M\times 50.00mL)}{10.00mL}=0.5225M$

So, concentration solution A was 0.5225 M

8 0

3 years ago

Choose the number of significant figures indicated 0.06

Alex17521 [72]

Answer:

Explanation:

8 0

2 years ago

We observe a distant object in space and see that the spectral lines for hydrogen in the object's light appear at a shorter wave

MrMuchimi

Answer:

This tells us the radial velocity of the object and that the object is approaching or coming towards us.

Explanation:

Certain chemicals radiate with particular wavelengths or colors when their temperature is raised or when they are charged electrically. Also observable are dark strokes separating the spectrum known as absorption lines

These spectral lines of chemicals are well known as stated above and from the phenomenon of Doppler effect, spectroscopy can be used to detect the movement of a distant object by the change of the emitted frequency of the wavelength

The Doppler effect is used in calculating the radial velocity of a distant object due to the fact that an approaching object compresses its emitted signal wavelength while a receding object has a longer wavelength than normal

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3 years ago

Draw structures from the following names, and determine which compounds are optically active:(c) 1,2-dibromo-2-methylbutane

dolphi86 [110]

The given compound 1,2-dibromo-2-methylbutane is an optically active compound .

Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .

It has chiral center.

Here , the chiral carbon is attached to the 4 distinct groups such as : methyl , ethyl , bromine , bromomethane .

<h3>What is di-symmetry?</h3>

Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

Have Sp3 hybridized center (4sigma bond ) .

4 distinct group is attached to the chiral atom. form non -superimposable mirror image .

<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

They differ in their behavior towards plane polarized light (ppl) .

Learn more about chiral center here:

brainly.com/question/9522537

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8 0

1 year ago

Koii zinda he kya -_+<br><br>what is ions???

satela [25.4K]

Answer:

An ion is defined as an atom or molecule that has gained or lost one or more of its valence electrons, giving it a net positive or negative electrical charge.

Explanation:

I am here zinda -_+...

3 0

2 years ago