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Talja [164]
3 years ago
13

A conducting sphere has a net charge of 4.8  1017

Chemistry
1 answer:
vodomira [7]3 years ago
5 0
A net charge of the sphere is the overall charge of the sphere. If it says that there are excess electrons, it means that the net charge is negative. Also, the quantity of charge of sub particles are very small so that must be 10 to the power of negative 17. So, I think the net charge is -4.8×10⁻¹⁷ Coulombs.

Then, we use the electrical charge of an electron which is equal to 1.60217662×10⁻¹⁹ C/electron. Therefore,

-4.8×10⁻¹⁷ Coulombs * 1 electron/-1.60217662×10⁻¹⁹ C = 299.592

Therefore, there are approximately 300 excess electrons.
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klio [65]
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7 0
3 years ago
barium chloride (Ba(CIO3)2) breaks down to form barium chloride and oxygen. what is the balanced equation for this equation?
kompoz [17]

Answer:

Ba(ClO₃)₂ → BaCl₂ + 3 O₂

Explanation:

When exposed to heat, barium chlorate (Ba(ClO₃)₂ breaks down into an inorganic compound (Barium chloride - BaCl₂) and a molecule (Oxygen - O₂).

6 0
4 years ago
Solid calcium carbide, CaC2, reacts with water to form an aqueous solution of calcium hydroxide and acetylene gas, C2H2. Express
Lina20 [59]

Answer:  CaC_2(s)+H_2O(l)\rightarrow Ca(OH)_2(aq)+C_2H_2(g)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The solutions in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas. Liquids are represented by (l) and gases are represented by (g).

The balanced chemical reaction is:

CaC_2(s)+2H_2O(l)\rightarrow Ca(OH)_2(aq)+C_2H_2(g)

4 0
3 years ago
In which orbitals would the valence electrons for selenium (Se) be placed?
SOVA2 [1]
The valence electrons of Selenium (Se) would be placed in the s and p orbitals.

Hope I could help!
6 0
4 years ago
Which of the above solutions could be used to remove lead from lead (II) nitrate?
alisha [4.7K]

Ni solution could be used to remove lead from lead (II) nitrate.

Explanation:

The removal of lead from lead nitrate will take place by displacement reaction.

In displacement reaction less reactive element is displaced by more reactive element form it compound.

The reactivity is decided by the placement of metal in the activity series.

A metal which is at higher position in the activity series will be able to displace the metal or element having lower position.

From the options given we will check their position in the activity series in comparison to Pb

Cu is lower in series than Pb hence cannot displace.

Hg is placed lower in the series than Pb hence cannot displace Pb.

Ag is placed lower than Pb in the series hence cannot displace Pb.

Ni is placed above the Pb in activity series hence can displace lead.

8 0
3 years ago
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