An aqueous potassium iodate (KIO3) solution is made by dissolving 553 grams of KIO3 in sufficient water so that the final volume

Question

3 years ago

8

of the solution is 2.10 L.
Calculate the molarity of the KIO3 solution.

2 answers:

professor190 [17] · Answer 1 · 2022-01-13T11:24:27+03:00

Answer: 1.229M

Explanation:

To get the molarity of KIO3, we must first calculate the number of mole of KIO3 that dissolves in 2.10 L of the solution

This can be achieved by doing the following:

MM of KIO3 = 39 + 127 + (3 x 16) = 214g/mol

Mass conc of KIO3 = 553g

Number of mole = Mass conc. /molar Mass

Number of mole = 553g/214

Number of mole = 2.58moles

We can solve for the molarity by using:

Molarity = number of mole / Volume

Molarity = 2.58/2.1

Molarity = 1.229M

Therefore, the molarity of KIO3 solution is 1.229M

liberstina [14] · Answer 2 · 2022-01-13T09:32:44+03:00

3 0

Answer:

M KIO3 = 1.254 mol/L

Explanation:

∴ w KIO3 = 553 g

∴ mm KIO3 = 214.001 g/mol

∴ volumen sln = 2.10 L

⇒ mol KIO3 = (553 g)×(mol/210.001 g) = 2.633 mol

⇒ M KIO3 = (2.633 mol KIO3 / (2.10 L sln)

⇒ M KIO3 = 1.254 mol/L