Answer:
0.011 moles
Explanation:
Applying,
PV = nRT.................... Equation 1
Where P = Pressure, V = Volume, n = number of moles, R = Molar gas constant, T = Temperature.
Make n the subject of the equation
n = PV/RT.................. Equation 2
From the question,
Given: P = 105 kPa = (105×0.00986923) = 1.036 atm, V = 250 mL = 0.25 L, T = 23 °C = (273+23) = 296 °C
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
n = (1.036×0.25)/(0.082×296)
n = 0.011 moles
Answer:
It determines how the molecule functions.- B.
Answer:
The hormone glucagon secreted by the pancreatic cells cause the release of glucose from the body's storage.
Explanation:
The pancreas is an organ found inside the abdomen. This organ produces hormones such as:
- Insulin
- Glucagon
- Somatostatin
- Vasoactive intestinal peptide
Insulin and glucagon are considered primary hormones secreted by the pancreas.
Upon skipping a meal, leading to a drop in blood sugar levels, glucagon is secreted by the pancreas. This hormone then acts on the liver to stimulate the conversion of stored up glycogen present in the liver into glucose. This produced glucose is then released into the blood stream, availing the boy glucose for energy.
It depends on how many electrons are already in the outer shell.
If it is a large amount (if it is almost to the maximum), then it will want to borrow from another atom.
But if it is close to empty then it will want to give away so it will go back to the inner ring with will be full.
Hope this helps, good luck!
Answer:
a, and f.
Explanation:
To be deprotonated, the conjugate acid of the base must be weaker than the acid that will react, because the reactions favor the formation of the weakest acid. The pKa value measures the strength of the acid. As higher is the pKa value, as weak is the acid. So, let's identify the conjugate acid and their pKas:
a. NaNH2 will dissociate, and NH2 will gain the proton and forms NH3 as conjugate acid. pKa = 38.0, so it happens.
b. NaOH will dissociate, and OH will gain the proton and forms H2O as conjugate acid. pKa = 14.0, so it doesn't happen.
c. NaC≡N will dissociate, and CN will gain a proton and forms HCN as conjugate acid. pKa = 9.40, so it doesn't happen.
d. NaCH2(CO)N(CH3)2 will dissociate and forms CH3(CO)N(CH3)2 as conjugate acid. pKa = -0.19, so it doesn't happen.
e. H2O must gain one proton and forms H3O+. pKa = -1.7, so it doesn't happen.
f. CH3CH2Li will dissociate, and the acid will be CH3CH3. pKa = 50, so it happens.
