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noname [10]
3 years ago
13

A satellite is composed of 30 modular units, each of which is equipped with a set of sensors, some of which have been upgraded.

Each unit contains the same number of non-upgraded sensors. If the number of non-upgraded sensors on one unit is 1/5 the total number of upgraded sensors on the entire satellite, what fraction of the sensors on the satellite have been upgraded?a) 5/6
b) 1/5
c) 1/6
d) 1/7
e) 1/24
Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0

Answer:

\frac{1}{7}

Step-by-step explanation:

The satellite has 30 modular units.

There are equal numbers of non-upgraded sensors in each unit.

Let us assume that on the entire satellite there are x numbers of upgraded sensors.

Then as per the given condition, there are \frac{x}{5} number of non-upgraded sensors in one unit.

Therefore, the number of non-upgraded sensors on the entire satellite is \frac{30x}{5} =6x

Hence, total number of sensors in the satellite is (x+ 6x) =7x

Therefore, the required fraction of the upgraded sensors is \frac{x}{7x} =\frac{1}{7}. (Answer)

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Answer:

8x-4

Step-by-step explanation:

(3x-5)+(5x+1)

=3x-5+5x+1

=8x-4

5 0
3 years ago
What’s the answer for x??
zubka84 [21]

Answer:

3x+85= 21

or, 3x= 85- 21

or, 3x= 64

or,x= 64/3

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Step-by-step explanation:

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8 0
3 years ago
Use the graph below to determine a1 and d for the sequence. graphed sequence showing point 1, negative 10, point 2, negative 7,
Sonja [21]

Answer:

a_1=-10

d=3

Step-by-step explanation:

we know that                              

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)                      

Let                                          

a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5

Find the difference between one term and the next

a_2-a_1=-7-(-10)=3              

a_3-a_2=-4-(-7)=3                  

a_4-a_3=-1-(-4)=3                        

a_5-a_4=2-(-1)=3                              

a_6-a_5=5-2=3                                                        

The difference between one term and the next is a constant        

This constant is the common difference                  

so                                                                                                                                  

The sequence graphed is an Arithmetic Sequence                    

therefore                                                                                    

The first term is a_1=-10                                    

The common difference is equal to d=3          

4 0
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3 0
3 years ago
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