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kolbaska11 [484]
3 years ago
6

{(-3, -5), (-1, 1), (0, 4), (1, 7)} list the domain amd range.

Mathematics
2 answers:
podryga [215]3 years ago
8 0

The domain are the numbers in the  X coordinates. So it would be -3, -1, 0, 1

The range is the numbers that are the Y coordinates. -5, 1, 4, 7

choli [55]3 years ago
8 0
In order to find out the answer you have to know what domain and range is.

Domain is x (here,y) while range is y (x,here). The answer to your problem is Domain: {-3,-1,0,1} and Range: {-5,1,4,7}.
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Answer:

One approach to this problem is to obtain the graph for the given equation.

We need to find every intersection those functions have with the axis 'x' and 'y'

starting with g(x)

g(x=0)=0-3, first point (0,-3) it iis the crossing point with 'x' axis

g(x)=0=x-3, second point (3,0) it iis the crossing point with 'y' axis

Lets do the same for f(x)

g(x=0)=0, this leads to the first point (0,0) it iis the crossing point with 'x' axis and also, with the 'y' axis

We dont need to find any other, since always y=x

By plotting we have the attached picture

Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.

Step-by-step explanation:

8 0
2 years ago
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The temperature dropped from 12° to 8° this was drop of how many degrees
lapo4ka [179]

Answer:

4°

Step-by-step explanation:

12-8=4

therefore the answer would be 4 degrees

6 0
3 years ago
x−2y+3z=8, 3y+z=12, −2x+2z=−4 Enter your answer, in the form (x,y,z), in the boxes in simplest terms.
Galina-37 [17]

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4 0
3 years ago
A cylinder and a cone have the same diameter: 8 inches. The height of the cylinder is 3 inches. The height of the cone is 18 inc
Bond [772]

The relationship is that two times the volume of cylinder is volume of cone

<em><u>Solution:</u></em>

Given that, cylinder and a cone have the same diameter: 8 inches

Diameter = 8 inches

Radius is diameter divided by 2

radius = \frac{diameter}{2}\\\\radius = \frac{8}{2} = 4

Radius = 4 inches

<u><em>Let us find the volume of cylinder and cone</em></u>

<u><em>Volume of cylinder:</em></u>

volume = \pi r^2 h

Radius = 4 inches

The height of the cylinder is 3 inches

height = 3 inches

Substituting the values, we get

volume = 3.14 \times 4^2 \times 3\\\\volume = 3.14 \times 16 \times 3\\\\volume = 150.72

Thus volume of cylinder is 150.72 cubic inches

<em><u>Volume of cone:</u></em>

volume = \frac{\pi r^2h}{3}

Radius = 4 inches

The height of the cone is 18 inches

height = 18 inches

Substituting the values, we get

volume = \frac{3.14 \times 4^2 \times 18}{3}\\\\volume = 3.14 \times 16 \times 6\\\\volume = 301.44

Thus volume of cone is 301.44 cubic inches

<em><u>What is the relationship between the volume of this cylinder and this cone?</u></em>

Volume of cylinder is 150.72 cubic inches

Volume of cone is 301.44 cubic inches

On observing the volume of cylinder and cone, we find that two times the volume of cylinder is volume of cone

2 \times \text{Volume of cylinder} = \text{Volume of cone}

2 \times 150.72 = 301.44\\\\301.44 = 301.44

Thus the relationship between the volume of this cylinder and this cone is that two times the volume of cylinder is volume of cone

5 0
4 years ago
11 black balls and 14 white balls are placed in an urn. two balls are then drawn in succession. what is the probability that the
Ulleksa [173]
11/25(14/24)+14/25(13/24)=
=154/600+182/600=
=336/600=14/25
6 0
3 years ago
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