How much atmosphere compressed to make oxygen pleasseeeeeee help me
1 answer:
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Answer:
Initial velocity = 39.2m/s
Maximum height is 78.4m
Explanation:
Given
Solving (a): Initial Velocity
Using first law of motion:
Where
<em /><em> [g represents acceleration due to gravity]</em>
Substitute these value in the above formula:
Take g as 9.8m/s²
<em>Hence, initial velocity = 39.2m/s</em>
Solving (b): Maximum Height
This will be solved using second equation of motion
This becomes
Substitute values for u, t and g
<em>Hence, the maximum height is 78.4m</em>
Answer:
, assuming that the meter stick is uniform with the center of mass precisely at the
mark.
Explanation:
Refer to the diagram attached. The meter stick could be considered as a lever. The string at the mark would then act as the fulcrum of this lever.
The mass at the
mark is at a distance of
to the right of the fulcrum at
.
The weight of the meter stick acts like a weight of
attached to the center of mass of this meter stick. Under the assumptions, this center of mass of this meter stick would be at the
mark, which is
to the right of the fulcrum at
.
Let be the mass attached to the meter stick at the
mark. This mass would be at a distance of
to the left of the fulcrum at
.
At equilibrium:
.
Solve for , the unknown mass attached to the meter stick at the
mark:
.
