Answer:
The surface charge density of the sheet is 1547.516 C/m²
Explanation:
Given;
force experienced by the proton, F = 14.0 μN
Electric field near an infinite sheet with surface charge density (σ) is given as;
E = σ/2ε₀
The force of attraction the proton experienced towards the sheet;
F = Eq
F = q(σ/2ε₀) 
where;
q is the charge of the proton
σ is the surface charge density of the sheet
ε₀ is the permittivity of free space

Therefore, the surface charge density of the sheet is 1547.516 C/m²
Answer:

Explanation:
Let's use Ohm's law:
or
(1)
Where:

We know the value of the voltage V, so we need to find the value of R in order to find I. Fortunately there is a relation between the resistivity of a conductor and its electrical resistance given by:
(2)
Where:

Keep in mind that the electrical resistivity of the gold is a known constant which is
and the cross sectional area of the conductor is calculated as:

Because we have a wire in this case, so we assume a cylindrical geometry.
Now replacing our data in (2)

Finally, we know R and V, so replacing these values in (1) we will be able to find the current:

337493603.8m/s²
Explanation:
Radius of the earth = 6.38 x 10¹⁶m
time = 24hr (86400s)
Unknown:
Centripetal acceleration = ?
Solution:
The centripetal acceleration is directed inward to keep the body from falling off the surface of the earth.
centripetal acceleration = 
where v is the velocity and r is the radius
also;
v = wr
where w is the angular velocity
substituting in the equation for centripetal acceleration gives;
a = w²r
also w = 
therefore;
a = 
a = 
a = 337493603.8m/s²
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