Answer:
Explanation:
T₁ = 700 + 273 = 973 k
T₂ = 330 + 273 = 603 k
Theoretical efficiency = T₁ - T₂ / T₁
= (973 - 603) / 973
= .38 OR 38%
Operating efficiency = .79 x 38
= 30.02 %
Heat input Q₁ , Heat output to sink Q₂ , conversion into power = Q₁ - Q₂
given Q₁ - Q₂ = 1.3 x 10⁹ W
efficiency = Q₁ - Q₂ / Q₁
Q₁ - Q₂ / Q₁ = 30.02 / 100
100Q₁ - 100Q₂ = 30.02Q₁
69.98 Q₁ = 100Q₂
Q₁ = 1.429 Q₂
Putting this in the relation
Q₁ - Q₂ = 1.3 x 10⁹ W
1.429Q₂ - Q₂ = 1.3 x 10⁹ W
.429Q₂ = 1.3 x 10⁹
Q₂ = 3.03 x 10⁹W
= 3.03 GW.
Answer:
The greater the luminosity of a star, the longer its period of oscillation.
When an electric current is flowing through a wire, there is a magnetic <em>field</em> produced. The lines of magnetic force are circles around the wire.
It’s important because if you were let’s say training to see how far you go in 10sec you need to record your data to see how much you are improving in that skill or something
Answer:
The total charge Q of the sphere is 
.
Explanation:
Given that,
Radius = 5 cm
Charge density 
We need to calculate the total charge Q of the sphere
Using formula of charge
Where, 
= charge density
V = volume
Put the value into the formula
Put the value into the formula
Hence, The total charge Q of the sphere is .
