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11111nata11111 [884]
3 years ago
8

7) A force of 500N exists between two identical point charges separated by a dis-

Physics
2 answers:
navik [9.2K]3 years ago
8 0

Answer:

q=9.43×10^-5C

Explanation:

F=kq^2/r^2

500= 9×10^9 × q^2/ (0.4)^2

500N×0.16m=9×10^9Nm^2C^2 × q^2

80/(9×10^9)= q^2

√(8.8889×10^9) = q

q= 9.43×10^-5C

since they are identical both charges, q=9.43×10^-5C

ioda3 years ago
5 0

Explanation:

f=500N

d=40cm=0.4m

=

\sqrt{500 \times 500 + .4 \times .4}

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