P=I^2 *R
600 =5.0^2 *R
R=24
Answer: 24 ohms
I hope it’s correcttttttt...
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Answer:
1832
Explanation:
From;
Δp Δx = h/4π
Δp = uncertainty in momentum
Δx = uncertainty in position
h= Plank's constant
But p =mv hence, Δp= Δmv
m= mass, v= velocity
mass of electron = 9.11 * 10^-31 Kg
Mass of proton = 1.67 * 10^-27 Kg
since m is a constant,
Δv = h/Δxm4π
For proton;
Δv = 6.6 * 10^-34/4 * 3.14 * 1.67 * 10^-27 * 1 * 10^-10
Δv = 315 ms-1
For electron;
Δv = 6.6 * 10^-34/4 * 3.14 * 9.11 * 10^-31 * 1 * 10^-10
Δv = 577000 ms-1
Ratio of uncertainty of electron to that of proton = 577000 ms-1/315 ms-1= 1832
resultant force = thrust – weight
acceleration = resultant force (newtons, N) divided by mass (kilograms, kg).
Acceleration = resultant force divided by mass
53N/0.56
=94.64 approximately 95
= 95m/s^2
This means that, every second, the speed of the rocket increases by 95m/s2
the S.I unit of Acceleration is meter per second square.