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Artyom0805 [142]
2 years ago
12

You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 275 N in the positive x di

rection to try and move the 61 kg refrigerator. The coefficient of static friction is 0.58. (a) How much static frictional force does the floor exert on the refrigerator
Physics
1 answer:
Volgvan2 years ago
8 0

Answer:

f = 347.08 N

Explanation:

The frictional force exerted by the floor on the refrigerator is given as follows:

f = \mu R = \mu W

where,

f = frictional force = ?

μ = coefficient of static friction = 0.58

W = Weight of refrigerator = mg

m = mass of refrigerator = 61 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

f = \mu mg\\f = (0.58)(61\ kg)(9.81\ m/s^2)\\

<u>f = 347.08 N</u>

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Answer:

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Explanation:

Let us apply the formula for the speed of a wave on a string that is under tension:

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Mass per unit length is given as:

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m = \frac{20 * 4.5}{85^2}\\\\m = \frac{90}{7225}\\ \\m = 0.0125 kg

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