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3 years ago

Which statement explains what happens to older crust during seafloor spreading?

Physics

1 answer:

ikadub [295]3 years ago

6 0

Answer:

the last one, It moves away from a mid-ocean ridge.

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What was the kickball was originally named

Misha Larkins [42]

Answer:

kick baseball

Explanation:

The sport of kickball, originally called "kick baseball," has roots going back to the early part of the 20th century in Cincinnati, Ohio. In the 1920's physical education teachers used kickball to teach the basics of baseball

5 0

3 years ago

Read 2 more answers

You leave the doctor's office after your annual checkup and recall that you weighed 689 N in her office. You then get into an el

son4ous [18]

Answer: 0.455 m/s^2

Explanation:

f = ma = m x 9.8=689 (the mass is constant)

m = 78.3

now on the elevator

f = 721 = m x a

a= 10.26

the elevator is moving down because there is a increase in weight. the acceleration of elevator = 10.26-9.8 = 0.455

8 0

4 years ago

If the bus had a mass of 1,021kg how much does the bus weigh?

goblinko [34]

Weight of the bus= mass x acceleration due to gravity = 1021x9.8 = 10005.8 N. Hope it helps.

4 0

4 years ago

An alpha particle collides with an oxygen nucleus, initially at rest. The alpha particle is scattered at an angle of 25.0° above

Greeley [361]

Answer:

$v_{i}= 19\times 10^5\ m/s$

Explanation:

given,

scattering angle of alpha particle = 25.0° above its initial direction of motion

oxygen nucleus recoils at = 50.0° below this initial direction.

final speed of the oxygen = 2.08×10⁵ m/s

mass of alpha particle = 4.0 u

mass o oxygen nucleus = 16 u

momentum conservation along x- axis

$m_{a}v_{i} = m_a v_a cos\theta + m_o v_o cos\theta$

$4v_{i} = 4\times v_a cos25^0 + 16\times 2.08 \times 10^5 cos50^0$

$v_{i}= \dfrac{3.625\times v_a+ 21.39\times 10^5}{4}$ ....(1)

Along y-direction

$0 = m_av_a sin \theta - m_ov_o sin\theta$

$0 = 4\times v_a sin 25 - 16\times 2.08 \times 10^5 sin50^0$

$v_a = \dfrac{25.49 \times 10^5}{1.69}$

$v_a = 15.082\times 10^5\ m/s$

putting value in equation (1)

$v_{i}= \dfrac{3.625\times 15.082\times 10^5+ 21.39\times 10^5}{4}$

$v_{i}= 19\times 10^5\ m/s$

5 0

4 years ago

A geostationary satellite orbits the Earth in 24 hours along an orbital path that is parallel to an imaginary plane drawn throug

PIT_PIT [208]

Answer:

approximately 35,786 km

Explanation:

A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level. It maintains the same position relative to the Earth's surface.

7 0

3 years ago