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2 years ago

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Mathematics

1 answer:

kifflom [539]2 years ago

4 0

Answer:

1 2/3k or 1.666666666...

Step-by-step explanation:

Take 5k and put it into a fraction (x/5) and put an = and then next to it you put 1/3 (since that is how far he walked). multiply the 1 by the 5 to get 5. then do 5/3. you get 1.6666666666........ or 1 2/3k

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If the can of dogfood holds 8 ounces and the bag of dogfood holds 30 times the volume , how many pounds of dogfood does the bag

Maru [420]

Answer:

15 pound in a bag

Step-by-step explanation:

one can= 8 oz

one bag= 30 times the amount in a can

8 oz x 30 = 240 oz in a bag

Question asked how many pound is in one bag of dog food:

We know that 16 oz = 1 pound

240 oz = x pound

To find x pound we divide 240 oz by 16 oz-->

240 oz/ 16 oz = 15 pound

7 0

3 years ago

A researcher tests five individuals who have seen paid political ads about a particular issue. These individuals take a multiple

devlian [24]

Answer:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

Step-by-step explanation:

Information given

48, 41, 40, 51, and 50

The sample mean and deviation can be calculated with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=46$ represent the mean height for the sample

$s=5.148$ represent the sample standard deviation

$n=5$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis to test

We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:

Null hypothesis: $\mu = 40$

Alternative hypothesis: $\mu \neq 40$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

6 0

3 years ago

Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 10 Allen's hummingb

ruslelena [56]

Answer: provided in the explanation segment

Step-by-step explanation:

(a). from the question, we can see that since that б is known, we can use standard normal, z.

we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?

⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;

x ± z * б / √m

which is

3.15 ± 1.28 * 0.32/√10

= 3.15 ± 0.1295 = 3.0205 or 3.2795

(b). normal distribution of weight (c) б is known

(c). option (a) and (e) are correct

(d). from the question, let sample size be given as S

this gives';

1.28 * 0.32/√S = 0.15

√S = (1.28 * 0.32) / 0.15 = 2.73

S = 7.4529

cheers i hope this helps

6 0

3 years ago

Tim is investigating the relationship between the number of years since a tree was planted and the height of the tree in feet. H

wolverine [178]

Answer: There is not a good prediction for the height of the tree when it is 100 years old because the prediction given by the trend line produced by the regression calculator probably is not valid that far in the future.

Step-by-step explanation:

Years since tree was planted (x) - - - - height (y)

2 - - - - 17

3 - - - - 25

5 - - - 42

6 - - - - 47

7 - - - 54

9 - - - 69

Using a regression calculator :

The height of tree can be modeled by the equation : ŷ = 7.36X + 3.08

With y being the predicted variable; 7.36 being the slope and 3.08 as the intercept.

X is the independent variable which is used in calculating the value of y.

Predicted height when years since tree was planted(x) = 100

ŷ = 7.36X + 3.08

ŷ = 7.36(100) + 3.08

y = 736 + 3.08

y = 739.08

Forward prediction of 100 years produced by the trendline would probably give an invalid value because the trendline only models a range of 9 years prediction. However, a linear regression equation isn't the best for making prediction that far in into the future.

3 0

3 years ago

Christina will be retiring next month from her job after 35 years as a school bus driver. Over the last 35 years, Christina’s an

liubo4ka [24]

D at least 1722.08 because you multiply 22042 by 42 then you divide by 100 and add 1375 to get d at least $1375.

I Hope This Helped!!

8 0

3 years ago

Read 2 more answers