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Vikentia [17]
3 years ago
5

How many 6 digit pin numbers are possible if the digits are repeated?

Mathematics
2 answers:
andriy [413]3 years ago
5 0

Answer:

10000

Step-by-step explanation:

forsale [732]3 years ago
5 0

Answer:

there are 1000000 possible 6 digit pin numbers

Step-by-step explanation:

one way to think about this is it can be any number from 000000 to 999999.

the reason the answer is 1000000 and not 999999 is because 000000 is also a valid pin number.

sorry if this is confusing!

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Louren measures the distance around her circular mirror to
Veseljchak [2.6K]

Answer:

53 cm.

Step-by-step explanation:

Circumference = pi times diameter

We are trying to find diameter so rearrange

Circumference/pi = diameter

166.5/pi = 52.998596

Approximately 53 centimeters of lace

3 0
3 years ago
The total cost of five pens and eight mechanical pencils is 12.65. The cost of each mechanical pencil is 0.75 cents. Which repre
Tanya [424]

Answer:

the cost of each pen is 1.33

Step-by-step explanation:

if you multiply 0.75 by 8 you get 6 after that you subtract 6 from 12.65 which means you have 6.65 which you divide by 5 which equals 1.33  

7 0
3 years ago
Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
Given vectors a=(-1,-2), b=(-2,3), c=(3,-1), d=(-3,2) find the dot product of b and d.
goldfiish [28.3K]

hope it helps u.........

6 0
3 years ago
Divide the following polynomial 27x^2-9a/3
ryzh [129]
<span>(27x^2-9a)/3
= 9x^2 - 3a

hope it helps</span>
6 0
3 years ago
Read 2 more answers
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