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bixtya [17]
3 years ago
12

Kiera's dance class starts at 4:30 p.m. and ends at 6:15 p.m. How long is her dance class?

Mathematics
2 answers:
mash [69]3 years ago
4 0
1 hour and 45 minutes, I explained it on the last one of this copy of the question
oee [108]3 years ago
3 0
4:30 to 5:30 = 1 hour

5:30 to 6:15 = 30 minutes

1 hour + 30 minutes = 1 hr. and 30 min. long

HOPE THIS HELPED
:)
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If Trent has 11 quarters and dimes in his pocket, and they have a combined value of 200 cents, how many of each coin does he hav
allsm [11]

Answer:

Trent has 6 quarters and 5 dimes.

Step-by-step explanation:

Consider the provided information.

Let q =  Number of quarters

d = Number of dimes.

Trent has 11 quarters and dimes.

q+d=11

q=11-d

The worth of a quarter is 25 cents.

The worth of a dimes is 10 cents

25q+10d=200

Substitute the value of q in above equation.

25(11-d)+10d=200

275-25d+10d=200

15d=75  

d=5  

Substitute the value of d in q=11-d

q=11-5

q=6

Hence, Trent has 6 quarters and 5 dimes.

4 0
3 years ago
Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
20 POINTS FOR AN ANSWER PLEASE!!!
Anna007 [38]

Answer:12 feet

Step-by-steps:

1cm:4ft

4x3=12

7 0
3 years ago
Lindsay needs a jewelr To repair her earrings jewelry is offering her services for an initial $125 in addition to $15 per hour j
FinnZ [79.3K]
They charge the same amount in 5 hours.
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3 years ago
The surface area of a cylinder consists of the sum of the areas of what shapes?
Paraphin [41]
<span>The surface area of a cylinder includes the bases which are circles and the side which is a rectangle</span>
5 0
2 years ago
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