Question

Calculate the resistance of a 900.-watt toaster

Answer 1

     Using the Definition of Potency, we have:

$P= \frac{V^2}{R}$
 
     Entering the unknowns:

$P= \frac{V^2}{R} \\ 900*W= \frac{(120*V)^2}{R} \\ R= \frac{14400*V^2}{900*V*A} \\ R=16* \frac{V}{A} \\ \boxed {R=16Ohm}$

If you notice any mistake in my english, please let me know, because i am not native.

Answer 2

Answer : Resistance is 16 ohms.

Explanation :

It is given that,

Power of toaster, $P=900\ Watt$

Voltage, $V=120\ V$

According to ohm's law, V = I R

Mathematically power is defined as :

$P=\dfrac{V^2}{R}$

or

$R=\dfrac{V^2}{P}$

$R=\dfrac{(120\ V)^2}{900\ W}$

$R=16\ \Omega$

So, the resistance of the toaster is 16 ohms.

Hence, this is the required solution.