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MrRa [10]
3 years ago
13

Calculate the resistance of a 900.-watt toaster

Physics
2 answers:
olasank [31]3 years ago
8 0
     Using the Definition of Potency, we have:

P= \frac{V^2}{R}
 
     Entering the unknowns:

P= \frac{V^2}{R}  \\ 900*W= \frac{(120*V)^2}{R} \\ R= \frac{14400*V^2}{900*V*A}  \\ R=16* \frac{V}{A}  \\ \boxed {R=16Ohm}

If you notice any mistake in my english, please let me know, because i am not native.

liubo4ka [24]3 years ago
5 0

Answer : Resistance is 16 ohms.

Explanation :

It is given that,

Power of toaster, P=900\ Watt

Voltage, V=120\ V

According to ohm's law, V = I R

Mathematically power is defined as :

P=\dfrac{V^2}{R}

or

R=\dfrac{V^2}{P}

R=\dfrac{(120\ V)^2}{900\ W}

R=16\ \Omega

So, the resistance of the toaster is 16 ohms.

Hence, this is the required solution.

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2 years ago
When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The mass is now displ
Ray Of Light [21]

Answer:

period of oscillations is 0.695 second

Explanation:

given data

mass m = 0.350 kg

spring stretches x = 12 cm = 0.12 m

to find out

period of oscillations

solution

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force = k × x   .........1

so force = mg =  0.35 (9.8)  = 3.43 N

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4 0
3 years ago
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2 years ago
Read 2 more answers
The work done to compress a spring with a force constant of 290.0 N/m a total of 12.3 mm is: a) 3.57 J b) 1.78 J c) 0.0219 J d)
iren2701 [21]

Answer:

Work done, W = 0.0219 J

Explanation:

Given that,

Force constant of the spring, k = 290 N/m

Compression in the spring, x = 12.3 mm = 0.0123 m

We need to find the work done to compress a spring. The work done in this way is given by :

W=\dfrac{1}{2}kx^2

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W = 0.0219 J

So, the work done by the spring is 0.0219 joules. Hence, this is the required solution.

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3 years ago
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