All categories

3 years ago

Describing Free Fall What is the only force that acts on a falling body when it is in free fall?

2 answers:

6 0

"Free Fall" MEANS that the only force acting on the object is
the force of gravity. It may be falling, but if there's any other
force acting on it besides gravity, like maybe air resistance,
then it's NOT in "free fall".

Levart [38]3 years ago

4 0

Answer:

gravity

Explanation:

on edg. 2020

You might be interested in

What types of substances tend to be acidic

Fynjy0 [20]

Generally speaking, there are two types of substances; acids and bases. Bases tend to be alkaline and have a higher Ph while acids are acidic and have a lower value on the Ph scale.

3 0

3 years ago

Read 2 more answers

Consider a positive charge Q and a point B twice as far away from Q as point A. What is the ratio of the electric field strength

Vikentia [17]

Answer:

$\frac{E_{A}}{E_{B}}=4$

Explanation:

The electric field is defined as the electric force per unit of charge, this is:

$E=\frac{F}{q}$ .

The electric force can be obtained through Coulomb's law, which states that the electric force between to electrically charged particles is inversely proportional to the square of the distance between them and directly proportional to the product of their charges. The electric force can be expressed as

$F=\frac{kQq}{r^{2}}$ .

By substitution we get that

$E=\frac{kQq}{qr^{2}}\\\\E=\frac{kQ}{r^{2}}$

Now, letting $E_{A}$ be the electric field at point A, letting $E_{B}$ be the electric field at point B, and letting R be the distance from the charge to A:

$E_{A}=\frac{kQ}{R^{2}}\\\\E_{B}=\frac{kQ}{(2R)^{2}}$ .

The ration of the electric fields is

$\frac{E_{A}}{E_{B}}=\frac{\frac{kQ}{R^{2}}}{\frac{kQ}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(4)R^{2}}}\\\\\\\frac{E_{A}}{E_{B}}=\frac{1}{\frac{1}{(4)}}\\\\\frac{E_{A}}{E_{B}}=4$

This means that at half the distance, the electric field is four times stronger.

4 0

3 years ago

The total pressure inside a 1.43 L cylinder at 28C is 1.03 atm. If the temperatures drops to -35C, and the volume remains the sa

Art [367]

Answer:

0.81452 atm

Explanation:

$P_1$ = Initial pressure = 1.43 L

$V_1=V_2$ = Volume

$T_1$ = Initial temperature = (28+273.15) K

$T_2$ = Final temperature = (-35+273.15) K

$P_2$ = Final pressure

From the ideal gas law we have

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow P_2=\dfrac{P_1V_1T_2}{T_2V_2}\\\Rightarrow P_2=\dfrac{1.03\times 1.43\times (273.15-35)}{(273.15+28)1.43}\\\Rightarrow P_2=0.81452\ atm$

The pressure in the cylinder is 0.81452 atm

8 0

3 years ago

Need QUICK answer!

Tresset [83]

Most likely the answer is B.

7 0

3 years ago

Read 2 more answers

A measurement of density (mass/volume) is performed by measuring the mass of a sample of a rough cubic piece of metal on a balan

koban [17]

Answer:

Random errorrs

1) Variations in the level of the eye when we measure the dimensions of the cubic piece using the metric rule.

2) Possible vibrations or disbalance when we measure the mass of the of the cylinder.

Systematic errors

3) Wrong calibration for the balance and that represent a measurement wrong

Explanation:

Previous concepts

Random error represent an statistical error associated to the effect random in the experiment.

Systematic error is a "repeatable error associated with faulty equipment or a flawed experiment design", so is an error non controlled.

Solution to the problem

So as we can see we have two possible types of errors : random and systematic errors. For this stuation the list of 3 errors required are:

Random errors

1) Variations in the level of the eye when we measure the dimensions of the cubic piece using the metric rule.

2) Possible vibrations or disbalance when we measure the mass of the of the cylinder.

Systematic errors

3) Wrong calibration for the balance and that represent a measurement wrong

8 0

4 years ago