2 years ago

What is the electric potential 12 cm away from a charge of –5.2 × 10^–6C?

1 answer:

8 0

The equation for electric potential of a point charge is:

V=(k*q)/r where k=9*10^11 N m²/C², q is the charge and r is the distance from the charge to the point in which we are calculating the potential.

q=-5.2*10^-6 C
r=12 cm = 0.12 m

Now we plug in the numbers and get:

V=-3.9*10^5 Volts, so the correct answer is the second one.

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a desktop computer and monitor together draw about 2 A of current they plug into a wall outlet that is 120 V what is the Resista

Delvig [45]

Answer:

$60 \Omega$

Explanation:

the relation between current, voltage and resistance in an electrical circuit is given by Ohm's law:

$V=IR$

where V is the voltage, I is the current and R is the resistance. In this problem, the current is I=2 A, the voltage is V=120 V, therefore we can arrange the previous equation and find the resistance:

$R=\frac{V}{I}=\frac{120 V}{2 A}=60 \Omega$