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GenaCL600 [577]
3 years ago
15

Two identical guitar strings are prepared such that they have the same length ( 0.62 m ) and are under the same amount of tensio

n. The first string is plucked at one location, primarily exciting the second harmonic. The other string is plucked in a different location, primarily exciting the third harmonic. The resulting sounds give rise to a beat frequency of 324 Hz . What is the wave propagation speed on the guitar strings?
Physics
1 answer:
Tanya [424]3 years ago
4 0

Answer:

The speed is 401.76m/s

Explanation:

To find the fundamental frequency we use

3rd.harmonic - 2nd.harmonic = 324Hz

And we know that

f=v/2L

So v=f2L

v= 324 x 2 x 0.62= 401.76m/s

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What is the centripetal acceleration of the tip of the fan blade?

6.0 m/s2

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3 years ago
During soccer practice, Maya kicked a soccer ball 37° off the ground at 25 m/s. Max, the goalie, caught the ball 60 m away from
amid [387]

Answer:

3.0 seconds

Explanation:

We can solve the problem by considering the horizontal motion of the ball only. In fact, the ball moves by uniform motion (constant speed) along the horizontal direction, since there are no forces acting in this direction. The horizontal speed of the ball is given by:

v_x = v_0 cos \theta = (25 m/s)(cos 37^{\circ})=19.97 m/s

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We also know that the ball travels a horizontal distance of d = 60 m, so we can find the time it takes to cover the distance by using the equation:

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8 0
3 years ago
Read 2 more answers
2 decimeters expressed in millimeters
Alenkinab [10]
Hi!
1 decimeter = 100 millimeters.
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3 0
3 years ago
A 747 airliner reaches its takeoff speed of 173 mi/h in 35.2 s. what is the magnitude of its average acceleration
wolverine [178]
<span>7.21 ft/s^2
       
Since you're looking for average acceleration, you can simply divide the change in velocity by the time. To make the calculation more reasonable, first convert the speed of 173 mi/h into ft/sec by multiplying by 5280 to convert from mi/h to ft/h and then dividing by 3600 to convert from ft/h to ft/s. 173 * 5280 / 3600 = 253.7333 ft/s Now divide the change in velocity by the time in seconds. 253.7333 ft/s / 35.2 s = 7.208333 ft/s^2 Rounding result to 3 significant figures gives 7.21 ft/s^2</span>
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3 years ago
If the law of conversation of momentum is true,then how does the total momentum before a collision compare to the total momentum
Oxana [17]
<h2>Answer:The total momentum before collision is equal to the total momentum after collision.</h2>

Explanation:

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When we consider collisions,take the system as the two bodies that are colliding.

There are no external forces acting on the system.The forces that one body exerts on other come under internal forces.

So,momentum can be conserved in this case.

So,the total momentum before collision is equal to the total momentum after collision.

4 0
3 years ago
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