Answer:
Explanation:
From the question we are told that:
Distance 
Acceleration 
Angular Velocity 
Generally the equation for Acceleration is mathematically given by
Answer:
Ans 171.875 m(according to the units)
Explanation:
As we know,
to find the distance, we need to use this eqn..
speed = distance/ time
So, time is 1.92 s (as given)
the speed is 330 m/s ( in air speed)
so to find it is easy to find by using this
eqn..
speed =distance/time
330 =distance/1.92
330/1.92 =distance
171.875 = distance
Answer:
The magnetic force on the wire at the moment is 2 micro-Newton/(Ampere-meter)
Explanation:
Formula for magnetic force is F = qvB*sin(theeta)
and B = μ*I / 2*pi*r
where
q = charge in coulomb
v = velocity
B = magnetic field strength
μ = permeability of free space
I = current
so from here we get B = (4*pi*10^(-7))(5) / 2*pi*0.01 = 0.0001-T
now ,
F = (2mC)*(10)*0.0001*sin(90)
F = 2 micro-Newton/(Ampere-meter)
The background radiation is associated with a temperature of about 2.73 Kelvins (not Celsius). There is no particular reason for it to be at this specific value. This temperature is a snapshot of an ongoing process taken at our point in time. This temperature continues to change from where it used to be - many orders of magnitude higher in the early stages of our universe model - to today's measured value. The expanding universe view implies this temperature continues to decline as the universe expands, as you pointed out. It is just happening on an extremely slow time scale that we consider this value to be a constant.
Answer:
The object for the converging lens is upright and 0.429 cm tall, the image of this converging lens is inverted and 1.375 cm high
Explanation:
Let
![d_{o}=distance of object[tex]\\f=focal length\\d_{i}=distance of image\\I_{h}=Image height](https://tex.z-dn.net/?f=d_%7Bo%7D%3Ddistance%20of%20object%5Btex%5D%5C%5Cf%3Dfocal%20length%5C%5Cd_%7Bi%7D%3Ddistance%20of%20image%5C%5CI_%7Bh%7D%3DImage%20height)
For diverging lens:
Magnification = 
Image height 
(negative sign means the image is virtual, inverted.
This image is 
meter to left of the center of the diverging lens.
The converging lens is located 0.08 m to the right of the diverging lens
The distance between the image of the diverging lens and center of the converging lens = 
The image of the diverging lens becomes the object of the converging lens.
