Two identical guitar strings are prepared such that they have the same length ( 0.62 m ) and are under the same amount of tensio
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<h2>Answer:</h2><h2>Explanation:</h2>
First, let's refer to the distance formula:
, where d is distance, v is velocity or speed and t is time.
Now, let's find the distance covered by each individual speed that the car had:
<h3>1. Speed 1.</h3>In order to use the formula, we need to convert minutes into hours since the speed is given in km/h.
21.1 min/60= 0.35 h.
Now, apply the distance formula.
d=(0.35h)*(86.8km/h)= 30.38 km.
<h3>2. Speed 2.</h3>Convert minutes to hours again and do the same calculations.
10.6min/60=0.18h
d=(0.18h)*(106km/h)= 19.08 km.
<h3>3. Speed 3.</h3>36.5min/60= 0.61h
d=(0.61h)*(30.9km/h)= 18.85 km.
<h3>4. Obtain the total distance.</h3>The total distance must be given by the addition of all individual distances traveled by the car on each speed:
Total distance= 30.38 km + 19.08 km + 18.85 km= 68.31 km.
<span>The runner is moving by uniformly accelerated motion, starting from rest (so, his initial velocity is zero). The law of motion of the runner is
</span>
<span>
where x(t) is the distance covered after time t, and a is the acceleration of the runner. By re-arranging the formula, we get
</span>
<span>
We know the runner has covered a distance of S=12m in t=4.0 s, and if we plug these numbers into the equation, we find the acceleration of the runner:
</span>
<span>
</span>
</span>
where x(t) is the distance covered after time t, and a is the acceleration of the runner. By re-arranging the formula, we get
</span>
We know the runner has covered a distance of S=12m in t=4.0 s, and if we plug these numbers into the equation, we find the acceleration of the runner:
</span>
</span>